题目内容
计算或化简:
(1)(-
)×3÷3×(-
)
(2)(-6)2÷(-
+
-
)
(3)-19
×38
(4)-42-|-3|+3×(-
)2.
(1)(-
| 1 |
| 3 |
| 1 |
| 3 |
(2)(-6)2÷(-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
(3)-19
| 18 |
| 19 |
(4)-42-|-3|+3×(-
| 1 |
| 3 |
分析:(1)先把除法转化成乘法,再进行约分,即可得出答案;
(2)先算乘方,再根据乘法的分配律分别进行计算,最后把所得的结果合并即可;
(3)先把-19
转化成(-20+
),再根据乘法的分配律分别进行计算即可;
(4)先算乘方,再去掉绝对值,然后再算乘法,最后把所得的结果相加即可.
(2)先算乘方,再根据乘法的分配律分别进行计算,最后把所得的结果合并即可;
(3)先把-19
| 18 |
| 19 |
| 1 |
| 19 |
(4)先算乘方,再去掉绝对值,然后再算乘法,最后把所得的结果相加即可.
解答:解:(1)(-
)×3÷3×(-
)
=(-
)×3×
×(-
)
=
;
(2)(-6)2÷(-
+
-
)
=36×(-2)+36×3-36×4
=-72+108-144
=-108;
(3)-19
×38
=(-20+
)×38
=-20×38+
×38
=-760+2
=-758;
(4)-42-|-3|+3×(-
)2
=-16-3+3×
=-19+
=-18
.
| 1 |
| 3 |
| 1 |
| 3 |
=(-
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
=
| 1 |
| 9 |
(2)(-6)2÷(-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
=36×(-2)+36×3-36×4
=-72+108-144
=-108;
(3)-19
| 18 |
| 19 |
=(-20+
| 1 |
| 19 |
=-20×38+
| 1 |
| 19 |
=-760+2
=-758;
(4)-42-|-3|+3×(-
| 1 |
| 3 |
=-16-3+3×
| 1 |
| 9 |
=-19+
| 1 |
| 3 |
=-18
| 2 |
| 3 |
点评:此题考查了有理数的混合运算,正确掌握运算顺序,即乘方运算(和以后学习的开方运算)叫做三级运算;乘法和除法叫做二级运算;加法和减法叫做一级运算.在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序.
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