题目内容
先化简,再求值.-xy+(10xy-3x2-2y2)-3(2xy-x2),其中x=
,y=-
.
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原式=-xy+10xy-3x2-2y2-6xy+3x2=3xy-2y2,
当x=
,y=-
时,原式=3×
×(-
)-2×(-
)2=-1-
=-
.
当x=
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