题目内容
计算:(x+1)(x+2)(x+3)(x+4).
【解析】原式=[(x+1)(x+4)][(x+2)(x+3)]
=(x2+5x+4)(x2+5x+6)
=[(x2+5x)+4][(x2+5x)+6]
=(x2+5x)2+10(x2+5x)+24
=x4+10x3+25x2+10x2+50x+24
=
x4+10x3+35x2+50x+24.
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题目内容
计算:(x+1)(x+2)(x+3)(x+4).
【解析】原式=[(x+1)(x+4)][(x+2)(x+3)]
=(x2+5x+4)(x2+5x+6)
=[(x2+5x)+4][(x2+5x)+6]
=(x2+5x)2+10(x2+5x)+24
=x4+10x3+25x2+10x2+50x+24
=x4+10x3+35x2+50x+24.
+d的值.
=9,则
的值为 .
2的结果是( )
D.①②⑤⑥