题目内容
先化简,再求值
÷
+
,其中x=
+2.
| x-5 |
| x2-9 |
| x2-2x-15 |
| x2+6x+9 |
| 1 |
| x-3 |
| 3 |
原式=
×
+
=
;
当x=
+2时.原式=
+l
| x-5 |
| (x-3)(x+3) |
| (x+3)2 |
| (x-5)(x+3) |
| 1 |
| x-3 |
| 2 |
| x-3 |
当x=
| 3 |
| 3 |
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