题目内容

(a-b)(an+an-1b+an-2b2+…+a2bn-2+abn-1+bn)=______.
(a-b)(an+an-1b+an-2b2+…+a2bn-2+abn-1+bn
=an+1+anb+an-1b2+…+a3bn-2+a2bn-1+abn-anb-an-1b2-an-2b3-…-a2bn-1-abn-bn+1
=an+1-bn+1
故答案是an+1-bn+1
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网