题目内容
先化简,再求值:2(x+y)(-y+x)-(x+y)2+(x-y)2,其中x=2,y=| 1 | 2 |
分析:先把原式去括号,再化简,然后把给定的值代入求值.
解答:解:2(x+y)(-y+x)-(x+y)2+(x-y)2
=2(x+y)(x-y)-(x+y)2+(x-y)2
=2(x2-y2)-x2-2xy-y2+x2-2xy+y2
=2(x2-y2-2xy),
∵x=2,y=
.
∴原式=2×(4-
-2)=
,
故答案为
.
=2(x+y)(x-y)-(x+y)2+(x-y)2
=2(x2-y2)-x2-2xy-y2+x2-2xy+y2
=2(x2-y2-2xy),
∵x=2,y=
| 1 |
| 2 |
∴原式=2×(4-
| 1 |
| 4 |
| 7 |
| 2 |
故答案为
| 7 |
| 2 |
点评:本题考查了整式的化简求值,解题的关键是把原式化为最简,再代值计算,此题比较繁琐,计算时一定要细心才行.
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