题目内容
分解因式:(1) x4-5x2+4;
(2) (2)(x+y)2-3x-3y-4;
(3)amb2n-5ambn-6am;
(4) (x+1)(x+3)(x+5)(x+7)+15.
答案:
解析:
解析:
| (1)(x+1)(x-1)(x+2)(x-2)
(2)(x+y+1)(x+y-4) (3)am(bn-6)(bn+1) (4)(x2+8x+10)(x2+8x+12)
|
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