题目内容
先化简,再求值:(
-
)÷
,其中a=
-1.
| 1 |
| a-2 |
| 1 |
| a+2 |
| 2 |
| 2-a |
| 3 |
(
-
)÷
=
÷
=
÷
=
×
=-
;
当a=
-1时,原式=-
=-
=-
=-(
-1)=1-
.
| 1 |
| a-2 |
| 1 |
| a+2 |
| 2 |
| 2-a |
=
| (a+2)-(a-2) |
| (a-2)(a+2) |
| 2 |
| 2-a |
=
| a+2-a+2 |
| (a-2)(a+2) |
| 2 |
| 2-a |
=
| 4 |
| (a-2)(a+2) |
| 2-a |
| 2 |
=-
| 2 |
| a+2 |
当a=
| 3 |
| 2 | ||
|
| 2 | ||
|
2(
| ||||
(
|
=-(
| 3 |
| 3 |
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