题目内容

计算:
(1)-14-(1-0.5)×
1
3
×[2-(-3)2]

(2)90°-(23°16′+17°23′)+19°40′÷6;
(3)-22÷
4
5
×(
3
4
-
4
5
)

(4)(x3-2y3-3x2y)-(3x3-3y3-7x2y).
(1)原式=-1-0.5×
1
3
×(-7)
=-1+
7
6

=
1
6

(2)原式=90°-40°39′+3°16′40″
=93°16′40″-40°39′
=52°37′40″;
(3)原式=-4×
5
4
×(-
1
20
)=
1
4

(4)原式=x3-2y3-3x2y-3x3+3y3+7x2y
=(1-3)x3+(-2+3)y3+(-3+7)x2y
=-2x3+y3+4x2y.
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网