题目内容
在实数范围内分解因式:
(1)15a2-20ab=______
(2)x3-8x=______
(3)a3+ab2-2a2b=______
(4)m2+mx-n2+nx=______.
(1)15a2-20ab=______
(2)x3-8x=______
(3)a3+ab2-2a2b=______
(4)m2+mx-n2+nx=______.
(1)15a2-20ab=5a(3a-4b);
(2)x3-8x
=x(x2-8)
=x(x+
)(x-
);
(3)a3+ab2-2a2b
=a(a2+b2-2ab)
=a(a-b)2;
(4)m2+mx-n2+nx
=m2-n2+mx+nx
=(m+n)(m-n)+x(m+n)
=(m+n)(m-n+x).
故答案为:5a(3a-4b);x(x+
)(x-
);a(a-b)2;(m+n)(m-n+x).
(2)x3-8x
=x(x2-8)
=x(x+
| 8 |
| 8 |
(3)a3+ab2-2a2b
=a(a2+b2-2ab)
=a(a-b)2;
(4)m2+mx-n2+nx
=m2-n2+mx+nx
=(m+n)(m-n)+x(m+n)
=(m+n)(m-n+x).
故答案为:5a(3a-4b);x(x+
| 8 |
| 8 |
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