题目内容
| 1 |
| x+1 |
| x+3 |
| x2-1 |
| x2+4x+3 |
| x2-2x+1 |
分析:先计算除法,再通分计算减法,最后把x的值代入计算即可.
解答:解:原式=
-
×
=
-
=
,
当x=-3时,原式=
=
.
| 1 |
| x+1 |
| x+3 |
| (x+1)(x-1) |
| (x-1)2 |
| (x+1)(x+3) |
=
| 1 |
| x+1 |
| x-1 |
| (x+1)2 |
=
| 2 |
| (x+1)2 |
当x=-3时,原式=
| 2 |
| (-3+1)2 |
| 1 |
| 2 |
点评:本题考查了分式的化简求值,解题的关键是注意通分、约分,以及分子分母的因式分解.
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