题目内容

a =-时,求代数式 

15a2-{-4a2+[ 5a-8a2-(2a2a )+9a2 ]-3a }

的值.

原式= 20a2-3a.评析:先化简,再代入求值.

               15a2-{-4a2+[ 5a-8a2-(2a2a )+9a2 ]-3a }

             = 15a2-{-4a2+[ 5a-8a2-2a2a+9a2 ]-3a }

          = 15a2-{-4a2+[ -a2+6a ]-3a }

          = 15a2-{-4a2a2+6a-3a }

          = 15a2-{-5a2+3a }

                       = 15a2+5a2-3a 

                       = 20a2-3a

           把a =-  代入,得

原式= 20a2-3a = 20 (-2-3 (-)= 45+

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