题目内容
解方程
(1)3x2-5x+2=0
(2)(x-3)2+2x(x-3)=0.
(1)3x2-5x+2=0
(2)(x-3)2+2x(x-3)=0.
(1)3x2-5x+2=0,
(3x-2)(x-1)=0,
3x-2=0,x-1=0,
x1=
,x2=1.
(2)(x-3)2+2x(x-3)=0,
(x-3)(x-3+2x)=0,
x-3=0,x-3+2x=0,
x1=3,x2=1.
(3x-2)(x-1)=0,
3x-2=0,x-1=0,
x1=
| 2 |
| 3 |
(2)(x-3)2+2x(x-3)=0,
(x-3)(x-3+2x)=0,
x-3=0,x-3+2x=0,
x1=3,x2=1.
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解方程x2+x-1=
时,如果设y=x2+x,那么原方程可化为( )
| 3 |
| x2+x |
| A、y2+y-3=0 |
| B、y2-y+3=0 |
| C、y2+y+3=0 |
| D、y2-y-3=0 |