题目内容
先化简,再求值:
÷(m-
)•
,其中m是方程2m2+4m-1=0的解.
| m2-6m+9 |
| m2-4 |
| 4m-9 |
| m-2 |
| 1 |
| m |
原式=
÷
•
=
÷
•
=
•
•
=
=
,
∵2m2+4m-1=0,
∴m2+2m=
,
∴原式=
=2.
| (m-3)2 |
| (m+2)(m-2) |
| m(m-2)-(4m-9) |
| m-2 |
| 1 |
| m |
=
| (m-3)2 |
| (m+2)(m-2) |
| (m-3)2 |
| m-2 |
| 1 |
| m |
=
| (m-3)2 |
| (m+2)(m-2) |
| m-2 |
| (m-3)2 |
| 1 |
| m |
=
| 1 |
| m(m+2) |
=
| 1 |
| m2+2m |
∵2m2+4m-1=0,
∴m2+2m=
| 1 |
| 2 |
∴原式=
| 1 | ||
|
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