题目内容
计算:
(1)(-1)3-
[4-(-3)2]
(2)2(4a2b-3ab)-(-5a2b+2ab)
(1)(-1)3-
| 1 |
| 3 |
(2)2(4a2b-3ab)-(-5a2b+2ab)
(1)原式=-1-
×(-5)
=-1+
=
;
(2)原式=8a2b-6ab+5a2b-2ab
=13a2b-8ab.
| 1 |
| 3 |
=-1+
| 5 |
| 3 |
=
| 2 |
| 3 |
(2)原式=8a2b-6ab+5a2b-2ab
=13a2b-8ab.
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