题目内容
先化简,后求值:| x-4 |
| x2-1 |
| (x-4)(x+1) |
| x2+2x+1 |
| 1 |
| x-1 |
分析:先计算除法,再计算加法,最后代入求值.
解答:解:原式=
×
+
=
+
=
当x=5时,原式=
=
.
| x-4 |
| (x+1)(x-1) |
| (x+1)2 |
| (x-4)(x+1) |
| 1 |
| x-1 |
=
| 1 |
| x-1 |
| 1 |
| x-1 |
=
| 2 |
| x-1 |
当x=5时,原式=
| 2 |
| 5-1 |
| 1 |
| 2 |
点评:本题是一道基础题,学生只要认真仔细就可正确解答.
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