题目内容
先化简,再求值:2(3m2-mn-
n2)-
(m2-2mn-4n2),其中m=-2,n=
.
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原式=6m2-2mn-n2-
m2+mn+2n2
=
m2-mn+n2,
当m=-2,n=
时,原式=
×4-(-2)×
+
=23
.
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=
| 11 |
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当m=-2,n=
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| 11 |
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