题目内容
化简:
=
-
=
.
| 2x-2 |
| 1-x2 |
-
| 2 |
| 1+x |
-
; | 2 |
| 1+x |
| 4m2-3mn |
| mn |
| 3m2+2mn |
| nm |
| m-5n |
| n |
| m-5n |
| n |
分析:第一个先分解因式,再进行约分即可;根据同分母分式的加减法则进行计算,最后约分即可.
解答:解:
=
=-
,
-
=
=
=
,
故答案为:-
,
.
| 2x-2 |
| 1-x2 |
| 2(x-1) |
| -(x+1)(x-1) |
| 2 |
| x+1 |
| 4m2-3mn |
| mn |
| 3m2+2mn |
| nm |
=
| 4m2-3mn-3m2-2mn |
| mn |
=
| m2-5mn |
| mn |
=
| m-5n |
| n |
故答案为:-
| 2 |
| 1+x |
| m-5n |
| n |
点评:本题考查了分式的混合运算的应用,主要考查学生的计算能力.
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