题目内容

计算化简:
x
x2+3x+2
+
x
x2+x-2
+
2
1-x2
原式=
x
(x+2)(x+1)
+
x
(x+2)(x-1)
+
2
(1+x)(1-x)

=
x(x-1)
(x+2)(x+1)(x-1)
+
x(x+1)
(x+2)(x+1)(x-1)
-
2(x+2)
(x+2)(x+1)(x-1)

=
x2-x +x2+x-2x-4
(x+2)(x2-1)

=
2x2-2x-4
(x+2)(x+1)(x-1)

=
2(x-2)(x+1)
(x+2)(x+1)(x-1)

=
2x-4
x2+x-2
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