题目内容
(2013•道外区一模)先化简,再求值:
÷(x-
),其中x=2sin60°+2cos60°.
| x+1 |
| x |
| x2+1 |
| 2x |
分析:首先把括号内的式子通分相减,然后把除法转化成乘法运算,然后计算乘法即可化简,然后对x的值进行化简,最后代入求解即可.
解答:解:原式=
÷(
-
)
=
÷
=
•
=
.
∵x=2×
+2×
=
+1
∴原式=
=
.
| x+1 |
| x |
| 2x2 |
| 2x |
| x2+1 |
| 2x |
=
| x+1 |
| x |
| x2-1 |
| 2x |
=
| x+1 |
| x |
| 2x |
| (x+1)(x-1) |
=
| 2 |
| x-1 |
∵x=2×
| ||
| 2 |
| 1 |
| 2 |
| 3 |
∴原式=
| 2 | ||
|
2
| ||
| 3 |
点评:本题考查了分式的混合运算,解答此题的关键是把分式化到最简,然后代值计算.
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