题目内容
解方程:
(1)7y+26=-5y+10
(2)5(x+2)=-2(5x-1)
(3)
-
=1
(4)
-
=1.5
(1)7y+26=-5y+10
(2)5(x+2)=-2(5x-1)
(3)
| 2x+1 |
| 3 |
| 5x-1 |
| 6 |
(4)
| 0.1x-0.2 |
| 0.2 |
| x+1 |
| 0.5 |
(1)7y+5y=10-26
12y=-16
y=-
;
(2)5x+10=-10x+2
5x+10x=2-10
15x=-8
x=-
;
(3)2(2x+1)-(5x-1)=6
4x+2-5x+1=6
4x-5x=6-2-1
-x=3
x=-3;
(4)
-2(x+1)=1.5
x-2-4(x+1)=3
x-2-4x-4=3
-3x=9
x=-3.
12y=-16
y=-
| 3 |
| 4 |
(2)5x+10=-10x+2
5x+10x=2-10
15x=-8
x=-
| 8 |
| 15 |
(3)2(2x+1)-(5x-1)=6
4x+2-5x+1=6
4x-5x=6-2-1
-x=3
x=-3;
(4)
| x-2 |
| 2 |
x-2-4(x+1)=3
x-2-4x-4=3
-3x=9
x=-3.
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