题目内容
(1)计算:(-1)3-|1-
|+(
)-2×(π-3.14)0-
(2)解方程:3(x-5)2=2(5-x)
| 2 |
| 1 |
| 2 |
| 8 |
(2)解方程:3(x-5)2=2(5-x)
(1)原式=-1+1-
+4×1-2
=-1+1-
+4-2
=4-3
;
(2)∵3(x-5)2+2(x-5)=0,
∴(x-5)[3(x-5)+2]=0,
∴x-5=0或[3(x-5)+2]=0,
∴x1=5,x2=
.
| 2 |
| 2 |
=-1+1-
| 2 |
| 2 |
=4-3
| 2 |
(2)∵3(x-5)2+2(x-5)=0,
∴(x-5)[3(x-5)+2]=0,
∴x-5=0或[3(x-5)+2]=0,
∴x1=5,x2=
| 13 |
| 3 |
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