ÌâÄ¿ÄÚÈÝ

·Û±ÊÊǽÌÊÒÄÚ¿ÕÆøµÄÖ÷ÎÛȾԴ£¨¿ÉÎüÈë¿ÅÁ£Î£¬·Û±ÊµÄÉú²ú¹ý³ÌÊÇ£º

¾«Ó¢¼Ò½ÌÍø

£¨1£©Ò½Ò©ÉÏ¿ÉÓÃʯ¸à¹Ì¶¨¹ÇÕÛ²¿Î»£®Êìʯ¸àÊǰ×É«·Ûĩ״£¬Éúʯ¸àÊÇÒ»ÖÖ¼áÓ²µÄ¹ÌÌ壬ҽÉú¸ø²¡ÈËÒ»¿ªÊ¼¹Ì¶¨¹ÇÕÛÓõÄʯ¸àÊÇ______£¨Ìѧʽ£©£®¹Ì¶¨Ê±·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ______
£¨2£©ÔÚÊìʯ¸àÖмÓÈëÉÙÁ¿µÄ¸ÊÓͺʹ¿¼î£¬¿ÉÖÆ³É¡°ÎÞ³¾¡±·Û±Ê£¬ÕâÊÇÀûÓøÊÓÍÎüʪÐÔºÜÇ¿µÄÐÔÖÊ£¬¿Éʹ·Û±ÊÒò³±Êª¶ø²»Æ¯³¾£¬¶ø¼ÓÈë´¿¼îµÄ×÷ÓÃÊÇÌá¸ß·Û±ÊµÄÓ²¶È£®ÆäÔ­ÀíÓû¯Ñ§·½³Ìʽ±íʾΪ______£®
£¨1£©Ê¹ÓÃʱ£¬Éúʯ¸àÓëË®·´Ó¦Éú³ÉÊìʯ¸àÒԴﵽĿ£¬Ò½Éú¸ø²¡ÈËÒ»¿ªÊ¼¹Ì¶¨¹ÇÕÛÓõÄʯ¸àÊÇÉúʯ¸à£¬»¯Ñ§Ê½ÊÇCaSO4?2H2O£¬ÓÉͼƬÐÅÏ¢¿ÉÖª£¬Êìʯ¸àºÍË®·´Ó¦Éú³ÉÉúʯ¸à£¬ËùÒÔ·½³ÌʽΪ£º2CaSO4?
1
2
H2O+3H2O¨T2CaSO4?2H2O£®
£¨2£©¼ÓÈë´¿¼î¿ÉÌá¸ß·Û±ÊµÄÓ²¶È£¬µ«´¿¼î±¾ÉíÓ²¶È²»´ó£¬ËùÒÔÊÇͨ¹ý·´Ó¦Éú³ÉÁËÒ»ÖÖÓ²¶È½Ï´óµÄÎïÖÊ£¬¸ù¾Ýʯ¸àºÍ´¿¼îµÄ×é³É£¬Éú³ÉµÄÎïÖÊÓ¦ÊÇ̼Ëá¸Æ£¬ËùÒÔ·´Ó¦·½³ÌʽΪ£ºCaSO4+Na2CO3¨TCaCO3¡ý+Na2SO4£®
¹Ê´ð°¸Îª£º£¨1£©CaSO4?2H2O£»2CaSO4?
1
2
H2O+3H2O¨T2CaSO4?2H2O£»£¨2£©CaSO4+Na2CO3¨TCaCO3¡ý+Na2SO4£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø