ÌâÄ¿ÄÚÈÝ
ÉϺ£È¾É«ÂøÍ·Ê¼þÔøÒý·¢Éç»á¹ã·º¹Ø×¢£®ËùνµÄÓñÃ×ÂøÍ·ÊÇÌí¼ÓÄûÃÊ»ÆÖÆÔì³öµÄ£¬ÄûÃʻƵĻ¯Ñ§Ê½Îª£¨C16H9N4O9S2Na3£©
£¨1£©ÄûÃÊ»ÆÓÉ ÖÖÔªËØ×é³É£®
£¨2£©ÄûÃÊ»ÆÖУ¬Çâ¡¢ÑõÁ½ÖÖÔªËØµÄÖÊÁ¿±ÈÊÇ £¨Ìî×î¼òÕûÊý±È£©£®£®
£¨3£©ÄûÃÊ»ÆÖУ¬Ëùº¬ÔªËØÖÊÁ¿·ÖÊý×î¸ßµÄÊÇ ÔªËØ£®
£¨4£©³«µ¼¿ÆÑ§Éú»î£¬Ìáó{½¡¿µË®Æ½£®ÏÂÁÐ˵·¨ÖУ¬ÄãÈÏΪºÏÀíµÄÊÇ £¨ÌîÐòºÅ£©£®
¢ÙÓù¤ÒµÓÃÑÎNaNO2ëçÖÆ»ðÍÈ
¢ÚÓÃÁò»ÇȼÉÕºóµÄÆøÌåѬÕô·ÛË¿ÒÔ´ïµ½¡°ÃÀ°×¡±Ð§¹û
¢ÛÔÚ½´ÓÍÖмÓÈëÌúÇ¿»¯¼Á¿ÉÔ¤·ÀȱÌúÐÔÆ¶Ñª£®
£¨1£©ÄûÃÊ»ÆÓÉ
£¨2£©ÄûÃÊ»ÆÖУ¬Çâ¡¢ÑõÁ½ÖÖÔªËØµÄÖÊÁ¿±ÈÊÇ
£¨3£©ÄûÃÊ»ÆÖУ¬Ëùº¬ÔªËØÖÊÁ¿·ÖÊý×î¸ßµÄÊÇ
£¨4£©³«µ¼¿ÆÑ§Éú»î£¬Ìáó{½¡¿µË®Æ½£®ÏÂÁÐ˵·¨ÖУ¬ÄãÈÏΪºÏÀíµÄÊÇ
¢ÙÓù¤ÒµÓÃÑÎNaNO2ëçÖÆ»ðÍÈ
¢ÚÓÃÁò»ÇȼÉÕºóµÄÆøÌåѬÕô·ÛË¿ÒÔ´ïµ½¡°ÃÀ°×¡±Ð§¹û
¢ÛÔÚ½´ÓÍÖмÓÈëÌúÇ¿»¯¼Á¿ÉÔ¤·ÀȱÌúÐÔÆ¶Ñª£®
¿¼µã£º»¯Ñ§Ê½µÄÊéд¼°ÒâÒå,ÔªËØÖÊÁ¿±ÈµÄ¼ÆËã,ÔªËØµÄÖÊÁ¿·ÖÊý¼ÆËã,ÑÇÏõËáÄÆ¡¢¼×È©µÈ»¯Ñ§Æ·µÄÐÔÖÊÓëÈËÌ彡¿µ
רÌ⣺»¯Ñ§ÓÃÓïºÍÖÊÁ¿Êغ㶨ÂÉ,»¯Ñ§ÓëÉú»î
·ÖÎö£º£¨1£©¸ù¾ÝÎïÖʵĻ¯Ñ§Ê½À´·ÖÎö£»£¨2£©¸ù¾Ý»¯ºÏÎïÖÐÔªËØÖÊÁ¿±ÈµÄ¼ÆËã·½·¨À´·ÖÎö£»£¨3£©¸ù¾Ý»¯ºÏÎïÖÐÔªËØÖÊÁ¿·ÖÊý´óСµÄ±È½Ï·½·¨À´·ÖÎö£»£¨4£©¸ù¾Ý»¯Ñ§ÎïÖÊÓëÈËÌ彡¿µµÄ¹ØÏµÀ´·ÖÎö£®
½â´ð£º½â£º£¨1£©ÓÉÄûÃʻƵĻ¯Ñ§Ê½C16H9N4O9S2Na3¿ÉÖª£¬ËüÊÇÓÉ6ÖÖÔªËØ×é³ÉµÄ£»¹ÊÌ6£»
£¨2£©ÄûÃÊ»ÆÖУ¬Çâ¡¢ÑõÁ½ÖÖÔªËØµÄÖÊÁ¿±ÈÊÇ£¨1¡Á9£©£º£¨16¡Á8£©=1£º16£®¹ÊÌ1£º16£»
£¨3£©ÄûÃʻƣ¨C16H9N4O9S2Na3£©ÖУ¬Ì¼¡¢Çâ¡¢µª¡¢Ñõ¡¢Áò¡¢ÄÆÔªËصÄÖÊÁ¿±ÈΪ£º£¨12¡Á16£©£º£¨1¡Á9£©£º£¨14¡Á4£©£º£¨16¡Á9£©£º£¨32¡Á2£©£º£¨23¡Á3£©£¬ÓÉ´Ë¿ÉÖªÆäÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊý×î´ó£¬¹ÊÌ̼£»
£¨4£©ÑÇÏõËáÊÇÒ»ÖÖÓж¾µÄÎïÖÊ£¬Áò»ÇȼÉÕ»á²úÉúÓж¾µÄ¶þÑõ»¯Áò£¬»áΣº¦ÈËÌ彡¿µ£¬¶ø¼ÓÌú½´ÓÍ¿ÉÓÐЧԤ·ÀÈËÌåµÄȱÌúÐÔÆ¶Ñª£¬¹ÊÌ¢Û£®
£¨2£©ÄûÃÊ»ÆÖУ¬Çâ¡¢ÑõÁ½ÖÖÔªËØµÄÖÊÁ¿±ÈÊÇ£¨1¡Á9£©£º£¨16¡Á8£©=1£º16£®¹ÊÌ1£º16£»
£¨3£©ÄûÃʻƣ¨C16H9N4O9S2Na3£©ÖУ¬Ì¼¡¢Çâ¡¢µª¡¢Ñõ¡¢Áò¡¢ÄÆÔªËصÄÖÊÁ¿±ÈΪ£º£¨12¡Á16£©£º£¨1¡Á9£©£º£¨14¡Á4£©£º£¨16¡Á9£©£º£¨32¡Á2£©£º£¨23¡Á3£©£¬ÓÉ´Ë¿ÉÖªÆäÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊý×î´ó£¬¹ÊÌ̼£»
£¨4£©ÑÇÏõËáÊÇÒ»ÖÖÓж¾µÄÎïÖÊ£¬Áò»ÇȼÉÕ»á²úÉúÓж¾µÄ¶þÑõ»¯Áò£¬»áΣº¦ÈËÌ彡¿µ£¬¶ø¼ÓÌú½´ÓÍ¿ÉÓÐЧԤ·ÀÈËÌåµÄȱÌúÐÔÆ¶Ñª£¬¹ÊÌ¢Û£®
µãÆÀ£º¸ÃÌâÒÔÐÂÎÅÈȵãΪ±³¾°£¬Ö÷Òª¿¼²éѧÉúÔËÓû¯Ñ§Ê½ÕÆÎÕÆäÔªËØ×é³ÉÖÖÀಢÄܼÆËã×é³É»¯ºÏÎïµÄ¸÷ÔªËØµÄÖÊÁ¿±È£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Îó涣ҧʱ·ÖÃÚµÄÒÏËᣨHCOOH£©»áʹÈËÌ寤·ôÖ×Í´£®ÏÂÁÐÓйØÒÏËáµÄ˵·¨ÕýÈ·ÊÇ£¨¡¡¡¡£©
| A¡¢ÒÏËáÊÇÑõ»¯Îï |
| B¡¢ÒÏËáÊÇÓÉ̼¡¢Çâ¡¢ÑõÈýÖÖÔ×Ó¹¹³É |
| C¡¢ÒÏËáÖÐ̼¡¢ÑõÔªËØµÄÖÊÁ¿±ÈΪ1£º2 |
| D¡¢ÒÏËáÖÐÇâÔªËØµÄÖÊÁ¿·ÖÊý×îС |
ÏÂÁÐʵÑé²Ù×÷ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢ ¼ÓÈÈÒºÌå |
| B¡¢ µÎ¼ÓÒºÌå |
| C¡¢ ¼ì²é×°ÖÃÆøÃÜÐÔ |
| D¡¢ ÍùÊÔ¹ÜÖмÓпÁ£ |
ÏÂÁÐÉè¼Æ·½°¸¿ÉÐУ¬ÇÒ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢ÓÃNaOHÈÜÒºÖÎÁÆÎ¸Ëá¹ý¶àÖ¢£ºNaOH+HCl¨TNaCl+H2O | ||||
| B¡¢ÊµÑéÊÒÓÃÏ¡ÁòËáÓëÍ·´Ó¦ÖÆÈ¡H2£ºH2SO4+Cu¨TCuSO4+H2¡ü | ||||
| C¡¢ÓÃÊÊÁ¿µÄÏ¡ÑÎËá³ýÈ¥Ìú±íÃæµÄÐâ¼££ºFe2O3+6HCl¨T2FeCl3+3H2O | ||||
D¡¢ÓõãȼµÄ·½·¨³ýÈ¥¶þÑõ»¯Ì¼ÆøÌåÖлìÓеÄÉÙÁ¿Ò»Ñõ»¯Ì¼£º2CO+O2
|
½ñÄê×Ô12ÔÂÒÔÀ´£¬¼ÃÄϵØÇø¿ÕÆøÖÊÁ¿±ÈÉϸöÔÂÓÐÁËÃ÷ÏÔ¸ÄÉÆ£¬ÏÂÁÐ×ö·¨Öв»»á¶Ô¿ÕÆøÖÊÁ¿²úÉúÓ°ÏìµÄÊÇ£¨¡¡¡¡£©
| A¡¢ÓÃú×÷ȼÁÏ |
| B¡¢Â¶Ìì·ÙÉÕÀ¬»ø |
| C¡¢Æû³µÅÅ·ÅÎ²Æø |
| D¡¢ÓÃÇâÆø×÷ȼÁÏ |