ÌâÄ¿ÄÚÈÝ


ijÊ߲˻ùµØÔÚÖÖÖ²Êß²Ëʱ£¬³£²ÉÓÃÏÂÁз½·¨¡£

(1)Ê©ÓÃÊÊÁ¿µÄµª·Ê¿ÉÒÔʹÖÖÖ²µÄÊß²ËҶɫŨÂÌ¡£

¢ÙÏÂÁл¯·ÊÖУ¬ÊôÓÚµª·ÊµÄÊÇ________(Ìî×Öĸ)¡£

A£®Ì¼ËáÇâï§(NH4HCO3

B£®²Ýľ»Ò(Ö÷Òª³É·ÖK2CO3

C£®Á׿ó·Û[Ca3(PO4)2]

¢Ú²Ýľ»Ò³Ê¼îÐÔ£¬ÄãÈÏΪËü________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)ÓëËùÑ¡µÄµª·Ê»ìºÏÊ©Óá£ÀíÓÉ£º________________________________________________________________________

________________________________________________________________________¡£

(2)ÓôóÅïÖÖÖ²Êß²Ëʱ£¬³£Ïò´óÅïÖв¹³äÆøÌå·ÊÁÏCO2¡£

¢ÙÄ¿µÄÊÇ´Ù½øÂÌɫֲÎïµÄ________×÷Óá£

¢ÚÈôÌṩµÄÆøÌå·ÊÁÏCO2ÖлìÓÐÉÙÁ¿µÄSO2£¬ÎªÁ˳ýÈ¥SO2£¬ÏÖÉè¼ÆÒÔÏÂÁ½ÖÖ·½·¨¡£

¼×·½·¨£º½«ÆøÌåͨ¹ý×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº¡£

ÒÒ·½·¨£º½«ÆøÌåͨ¹ý×ãÁ¿µÄÇâÑõ»¯ÄÆÈÜÒº¡£

[Ìṩ×ÊÁÏ] CO2ÓëNaHCO3²»»á·¢Éú·´Ó¦£»

SO2£«2NaHCO3===Na2SO3£«H2O£«2CO2£»SO2£«2NaOH===Na2SO3£«H2O¡£

ÇëÄãÀûÓÃÌṩµÄ×ÊÁϺÍËùѧµÄ֪ʶ·ÖÎö£ºÉÏÊö________·½·¨¿ÉÐÐ(Ìî¡°¼×¡±»ò¡°ÒÒ¡±)£¬ÀíÓÉÊÇ________________________________________________________________________

________________________________________________________________________¡£


(1)¢ÙA¡¡¢Ú²»ÄÜ¡¡¶þÕß»ìºÏÊ©ÓûáÉú³É°±Æø£¬½µµÍ·ÊЧ

(2)¢Ù¹âºÏ¡¡¢Ú¼×¡¡NaHCO3ÓëCO2²»·´Ó¦£¬ÓëSO2·´Ó¦£¬²»µ«ÄܳýÈ¥SO2£¬¶øÇÒ»¹ÄÜÔö¼ÓCO2µÄº¬Á¿


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø