ÌâÄ¿ÄÚÈÝ
6£®£¨1£©Ð´³öÏÂÁÐÒÇÆ÷µÄÃû³Æ£º
¢Ù¼¯ÆøÆ¿£¬¢ÚË®²Û£®
£¨2£©B×°ÖõÄ×÷ÓÃÊÇÎüÊÕÑõÆøÖеÄË®ÕôÆø£®
£¨3£©ÓÐͬѧÈÏΪСÃ÷Éè¼ÆµÄ×°ÖÃÓв»ºÏÀíÖ®´¦£¬ÔÒòÊÇÖÆµÃµÄÆøÌå²»¸ÉÔ
£¨4£©ÓÃH2O2ÈÜÒºÀ´ÖÆÈ¡ÑõÆøµÄ»¯Ñ§·½³ÌʽΪ2H2O2$\frac{\underline{\;MnO_2\;}}{\;}$2H2O+O2¡ü£¬
£¨5£©A×°Öû¹¿ÉÓÃÓÚʵÑéÊÒÖÆ±¸ÆøÌå¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCaCO3+2HCl=CaCl2+H2O+CO2¡ü£®
·ÖÎö £¨1£©¾Ý³£ÓÃÒÇÆ÷»Ø´ð£»
£¨2£©Å¨ÁòËá¾ßÓÐÎüË®ÐÔ£¬Êdz£ÓõÄÒºÌå¸ÉÔï¼Á£¬¿ÉÓÃÀ´ÎüÊÕÑõÆøÖеÄË®ÕôÆø£»
£¨3£©½áºÏÌâÒâ·ÖÎö£¬ÖÆÈ¡¸ÉÔïµÄÑõÆøÍ¨³£Ñ¡ÓÃÅÅ¿ÕÆø·¨£»
£¨4£©¾Ý·´Ó¦ÔÀíÊéд·½³Ìʽ£»
£¨5£©¾ÝÖÆÈ¡¶þÑõ»¯Ì¼µÄ·´Ó¦ÔÀíÊéд·½³Ìʽ£®
½â´ð ½â£º£¨1£©±êºÅÒÇÆ÷·Ö±ðÊǼ¯ÆøÆ¿ºÍË®²Û£»
£¨2£©Å¨ÁòËá¾ßÓÐÎüË®ÐÔ£¬Êdz£ÓõÄÒºÌå¸ÉÔï¼Á£¬¿ÉÓÃÀ´ÎüÊÕÑõÆøÖеÄË®ÕôÆø£»
£¨3£©ÒªµÃµ½¸ÉÔïµÄÑõÆø£¬²»ÄÜÓÃÅÅË®·¨£¬ÕâÑùÖÆµÃµÄÆøÌåÖк¬ÓÐË®·Ö£»
£¨4£©¹ýÑõ»¯ÇâÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÉú³ÉË®ºÍÑõÆø£¬·´Ó¦·½³ÌʽÊÇ£º2H2O2$\frac{\underline{\;MnO_2\;}}{\;}$2H2O+O2¡ü£»
£¨5£©ÈôÓÃÓÚÖÆÈ¡¶þÑõ»¯Ì¼£¬´óÀíʯºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬·´Ó¦·½³ÌʽÊÇ£ºCaCO3+2HCl=CaCl2+H2O+CO2¡ü£»
¹Ê´ð°¸Îª£º£¨1£©¼¯ÆøÆ¿£»Ë®²Û£»£¨2£©ÎüÊÕÑõÆøÖеÄË®ÕôÆø£»£¨3£©ÖÆµÃµÄÆøÌå²»¸ÉÔ£¨4£©2H2O2$\frac{\underline{\;MnO_2\;}}{\;}$2H2O+O2¡ü£»£¨5£©CaCO3+2HCl=CaCl2+H2O+CO2¡ü£®
µãÆÀ ±¾ÌâÄѶȲ»´ó£¬ÊìϤ¸÷ÖÖÒÇÆ÷µÄÓÃ;¼°·´Ó¦ÔÀí¡¢Å¨ÁòËá³£ÓÃÀ´¸ÉÔïÆøÌåµÈÊǽâ´ð´ËÀàÊÔÌâµÄ¹Ø¼ü£®
| A£® | ËÜÁÏ | B£® | ÃÞ»¨ | C£® | ºÏ³ÉÏ𽺠| D£® | ºÏ³ÉÏËά |
| A£® | ¶¼ÊÇÑõ»¯Îï | B£® | ¶¼ÄÜ·Ö½â·Å³öÑõÆø | ||
| C£® | ǰÕßÖк¬ÓÐÑõÆø | D£® | ×é³ÉÔªËØÏàͬ |