ÌâÄ¿ÄÚÈÝ

19£®Ä³´¿¼îÑùÆ·Öк¬ÓÐÉÙÁ¿NaCl£¬Ð¡Àöͬѧȡ¸ÃÑùÆ·23gÈ«²¿ÈܽâÓÚ150gË®ÖУ¬ÔÙÖðµÎ¼ÓÈë160gÏ¡ÑÎËᣮ·´Ó¦ÖвúÉúÆøÌåµÄÖÊÁ¿ÓëÑÎËáµÄÓÃÁ¿¹ØÏµÈçͼËùʾ£®
£¨1£©·´Ó¦½áÊøºó£¬²úÉúµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿ÊÇ8.8¿Ë£®
£¨2£©ËùÓÃÏ¡ÑÎËáµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿£¨Ð´³ö±ØÒªµÄ¼ÆËã¹ý³Ì£¬½á¹û±£Áôµ½0.1%£©
£¨3£©¼ÆË㵱ǡºÃÍêÈ«·´Ó¦Ê±£¬´ËʱËùµÃµ½µÄÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£¨Ð´³ö±ØÒªµÄ¼ÆËã¹ý³Ì£¬½á¹û±£Áôµ½0.1%£©

·ÖÎö ÓÉͼ¿ÉÒÔ¿´³öÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª8.8g£¬¸ù¾Ý¶þÑõ»¯Ì¼µÄÖÊÁ¿ºÍ¶ÔÓ¦µÄ»¯Ñ§·½³ÌʽÇóËã̼ËáÄÆ¡¢HClºÍÉú³ÉµÄÂÈ»¯ÄƵÄÖÊÁ¿£¬½ø¶ø¼ÆËã¶ÔÓ¦µÄÖÊÁ¿·ÖÊý£®

½â´ð ½â£ºÓÉͼ¿ÉÖª£¬Éú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª8.8g
Éè²Î¼Ó·´Ó¦µÄ̼ËáÄÆµÄÖÊÁ¿Îªx£¬Éú³ÉµÄÂÈ»¯ÄƵÄÖÊÁ¿Îªy£¬HClµÄÖÊÁ¿Îªz
Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü
106        73          117             44
x            z              y              8.8g
$\frac{106}{x}$=$\frac{73}{z}$=$\frac{117}{y}$=$\frac{44}{8.8g}$
x=21.2g
y=23.4g
z=14.6g
ËùÓÃÏ¡ÑÎËáµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ$\frac{14.6g}{160g}$¡Á100%¡Ö9.1%
Ç¡ºÃÍêÈ«·´Ó¦Ê±£¬´ËʱËùµÃµ½µÄÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý$\frac{23g-21.2g+23.4g}{23g+150g+160g-8.8g}$¡Á100%¡Ö7.8%
´ð£º£¨1£©·´Ó¦½áÊøºó£¬²úÉúµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿ÊÇ8.8¿Ë£®
£¨2£©ËùÓÃÏ¡ÑÎËáµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ9.1%£»
£¨3£©µ±Ç¡ºÃÍêÈ«·´Ó¦Ê±£¬´ËʱËùµÃµ½µÄÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ7.8%£®

µãÆÀ ¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆËãʱ£¬µÚÒ»ÒªÕýÈ·Êéд»¯Ñ§·½³Ìʽ£¬µÚ¶þҪʹÓÃÕýÈ·µÄÊý¾Ý£¬µÚÈý¼ÆËã¹ý³ÌÒªÍêÕû£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø