ÌâÄ¿ÄÚÈÝ

ÏÖÓÃÏÂÁÐ×°ÖÃÖÆÈ¡³õÖг£¼ûµÄÆøÌ壮Çë»Ø´ð£®
¾«Ó¢¼Ò½ÌÍø

£¨1£©Ð´³öÒÇÆ÷¢Ù¡¢¢ÚµÄÃû³Æ£º¢ÙÊÇ______£¬¢ÚÊÇ______£®
£¨2£©ÓøßÃÌËá¼ØÖÆÑõÆøÊ±£¬Ó¦Ñ¡Óõķ¢Éú×°ÖÃ______£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
£¨3£©ÀûÓÃC×°Öã¬Í¨¹ý·Ö½â·´Ó¦¿ÉÖÆµÃµÄÆøÌåÊÇ£¨Ð´»¯Ñ§Ê½£©______£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£¬ÆäÊÕ¼¯×°ÖÃӦѡÓÃ______£¨Ìî±àºÅ£©£®
£¨4£©ÀûÓÃC×°Öã¬Í¨¹ý¸´·Ö½â·´Ó¦¿ÉÖÆµÃµÄÆøÌåÊÇ£¨Ð´»¯Ñ§Ê½£©______£¬ÆäÊÕ¼¯×°ÖÃӦѡÓÃ______£¨Ìî±àºÅ£©£®
£¨5£©¼ìÑé×°ÖÃAÆøÃÜÐԵľßÌå·½·¨ÊÇ______£®
£¨1£©Êì¼ÇʵÑéÒÇÆ÷µÄÃû³Æ¼´¿É£¬¹Ê´ð°¸Îª£ºÊÔ¹Ü ¾Æ¾«µÆ£¨2·Ö£©
£¨2£©ÓøßÃÌËá¼ØÖÆÑõÆøÐèÒª¼ÓÈÈ£¬BÊǸö´íÎó×°Ö㬹ÊÑ¡A£¨1·Ö£©2KMnO4=K2MnO4+MnO2+O2¡ü£¨2·Ö£©
£¨3£©C×°Öò»ÐèÒª¼ÓÈÈ£¬»¹µÃÒªÓÃ·Ö½â·´Ó¦ÖÆÆøÌ壬ÄÇÓ¦¸ÃÊÇÑõÆø£¬ÑõÆøµÄÊÕ¼¯·½·¨ÓÐÁ½ÖÖ£®¹Ê´ð°¸Îª£ºO2£¨1·Ö£©2H2O2¨T2H2O+O2¡ü£¨2·Ö£©D»òF£¨1·Ö£©
£¨4£©C×°Öò»ÐèÒª¼ÓÈÈ£¬Í¨¹ý¸´·Ö½â·´Ó¦¿ÉÖÆµÃµÄÆøÌåÊǶþÑõ»¯Ì¼£¬¹ÊÑ¡CO2£¨1·Ö£©D£¨1·Ö£©
£¨5£©¿¼²é¼ì²é×°ÖÃµÄÆøÃÜÐÔÕâ¸öʵÑé»ù±¾²Ù×÷£¬¹Ê´ð°¸Îª£º½«Æäµ¼¹Ü¿ÚÒ»¶Ë½þÈëË®ÖУ¨1·Ö£©£¬ÔÙÓÃÊÖ½ôÎÕסÊԹܣ¨0.5·Ö£©£¬Èç¹ûË®ÖвúÉúÉÙÁ¿ÆøÅÝ£¨0.5·Ö£©£¬ËµÃ÷ÆøÃÜÐÔÁ¼ºÃ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø