ÌâÄ¿ÄÚÈÝ

3£®»¯Ñ§ÓÃÓïÊÇѧϰ»¯Ñ§µÄÖØÒª¹¤¾ß£®
£¨1£©ÓÃÊý×ֺͻ¯Ñ§·ûºÅ±íʾ£º
¢ÙÌúÀë×ÓFe3+                 ¢ÚÑõ»¯ÂÁÖÐÂÁÔªËØÏÔ+3¼Û$\stackrel{+3}{Al}$2O3
¢Û5¸öµâÔ­×Ó5I             ¢Ü笠ùÀë×ÓNH4+
£¨2£©ÓÃÏÂÁÐ×ÖĸÐòºÅÌî¿Õ£º
a£®»îÐÔÌ¿b£®Ì¼ËáÇâï§c£®ÑõÆød£®Ê¯Ä«
¢ÙcÓÃ×÷»ð¼ýµÄÖúȼ¼Á            ¢ÚaÓÃ×÷±ùÏä³ý³ô¼Á
¢ÛbÓÃÓÚũҵÉú²úÖеϝ·Ê        ¢ÜdÓÃÓÚÉú²úǦ±Êо
£¨3£©Ð´³öÏÂÁз´Ó¦µÄ·ûºÅ±í´ïʽ£º
¢Ù¶þÑõ»¯Ì¼ÓëÇâÑõ»¯¸ÆÈÜÒº·´Ó¦Ca£¨OH£©2+CO2¨TCaCO3¡ý+H2O    ¢ÚþÌõÔÚÑõÆøÖÐȼÉÕ2Mg+O2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO
¢Û¼ÓÈȸßÃÌËá¼Ø2KMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü                  ¢Ü¼ÓÈȼîʽ̼ËáÍ­Cu2£¨OH£©2CO3$\frac{\underline{\;\;¡÷\;\;}}{\;}$2CuO+H2O+CO2¡ü£®

·ÖÎö £¨1£©±¾Ì⿼²é»¯Ñ§ÓÃÓïµÄÒâÒå¼°Êéд£¬½âÌâ¹Ø¼üÊÇ·ÖÇ廯ѧÓÃÓïËù±í´ïµÄ¶ÔÏóÊÇ·Ö×Ó¡¢Ô­×Ó¡¢Àë×Ó»¹ÊÇ»¯ºÏ¼Û£¬²ÅÄÜÔÚ»¯Ñ§·ûºÅǰ»òÆäËüλÖüÓÉÏÊʵ±µÄ¼ÆÁ¿ÊýÀ´ÍêÕûµØ±í´ïÆäÒâÒ壬²¢Äܸù¾ÝÎïÖÊ»¯Ñ§Ê½µÄÊéд¹æÔòÕýÈ·ÊéдÎïÖʵĻ¯Ñ§Ê½£¬²ÅÄÜÊìÁ·×¼È·µÄ½â´ð´ËÀàÌâÄ¿£®
£¨2£©ÎïÖʵÄÐÔÖʾö¶¨ÎïÖʵÄÓÃ;£¬¸ù¾ÝÒÑÓеÄÎïÖʵÄÐÔÖʽøÐзÖÎö½â´ð¼´¿É£®
£¨3£©Ê×Ïȸù¾Ý·´Ó¦Ô­ÀíÕÒ³ö·´Ó¦Îï¡¢Éú³ÉÎï¡¢·´Ó¦Ìõ¼þ£¬¸ù¾Ý»¯Ñ§·½³ÌʽµÄÊéд·½·¨¡¢²½Ö裨д¡¢Åä¡¢×¢¡¢µÈ£©½øÐÐÊéд£®

½â´ð ½â£º£¨1£©¢ÙÀë×ӵıíʾ·½·¨£ºÔÚ±íʾ¸ÃÀë×ÓµÄÔªËØ·ûºÅÓÒÉϽǣ¬±ê³ö¸ÃÀë×ÓËù´øµÄÕý¸ºµçºÉÊý£¬Êý×ÖÔÚǰ£¬Õý¸º·ûºÅÔں󣬴ø1¸öµçºÉʱ£¬1ҪʡÂÔ£®¹ÊÌúÀë×ӿɱíʾΪ£ºFe3+£»
¢ÚÔªËØ»¯ºÏ¼ÛµÄ±íʾ·½·¨£ºÈ·¶¨³ö»¯ºÏÎïÖÐËùÒª±ê³öµÄÔªËØµÄ»¯ºÏ¼Û£¬È»ºóÔÚÆä»¯Ñ§Ê½¸ÃÔªËØµÄÉÏ·½ÓÃÕý¸ººÅºÍÊý×Ö±íʾ£¬Õý¸ººÅÔÚǰ£¬Êý×ÖÔÚºó£¬ËùÒÔÑõ»¯ÂÁÖÐÂÁÔªËØÏÔ+3¼Û£¬¹Ê¿É±íʾΪ£º$\stackrel{+3}{Al}$2O3£»
¢ÛÔ­×ӵıíʾ·½·¨¾ÍÊÇÓÃÔªËØ·ûºÅÀ´±íʾһ¸öÔ­×Ó£¬±íʾ¶à¸ö¸ÃÔ­×Ó£¬¾ÍÔÚÆäÔªËØ·ûºÅǰ¼ÓÉÏÏàÓ¦µÄÊý×Ö£®ËùÒÔ5¸öµâÔ­×Ó£¬¾Í¿É±íʾΪ£º5I£»
¢ÜÀë×ӵıíʾ·½·¨£ºÔÚ±íʾ¸ÃÀë×ÓµÄÔªËØ·ûºÅÓÒÉϽǣ¬±ê³ö¸ÃÀë×ÓËù´øµÄÕý¸ºµçºÉÊý£¬Êý×ÖÔÚǰ£¬Õý¸º·ûºÅÔں󣬴ø1¸öµçºÉʱ£¬1ҪʡÂÔ£®¹Ê笠ùÀë×ӿɱíʾΪ£ºNH4+£»
£¨2£©¢ÙÑõÆø¾ßÓÐÖúȼÐÔ£¬¿É×ö»ð¼ýµÄÖúÍÆ¼Á£¬¹ÊÌc£»
¢Ú»îÐÔÌ¿¾ßÓÐÎü¸½ÐÔ£¬ÓÃÓÚÈ¥³ý±ùÏäÖеÄÒì棬¹ÊÌa£»
¢Û̼ËáÇâï§Öк¬ÓÐÌ¼ÔªËØ£¬¿É×ö»¯·Ê£¬¹ÊÌb£»
¢ÜʯīÖÊÈí£¬ÑÕÉ«ÓÐÉîºÚÉ«£¬¿ÉÓÃ×÷Ǧ±Êо£¬¹ÊÌd£»
£¨3£©¢Ù¶þÑõ»¯Ì¼ÓëÇâÑõ»¯¸ÆÈÜÒº·´Ó¦Éú³É̼Ëá¸Æ¹ÌÌåºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O£»
¢ÚþÔÚÑõÆøÖÐȼÉյĻ¯Ñ§·½³ÌʽΪ£º2Mg+O2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO£»
¢Û¸ßÃÌËá¼ØÔÚ¼ÓÈÈÌõ¼þÏÂÉú³ÉÃÌËá¼Ø¡¢¶þÑõ»¯Ã̺ÍÑõÆø£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ2KMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü£»
¢ÜÍ­ÂÌÊÜÈÈ·Ö½âÉú³ÉÑõ»¯Í­£¨ºÚÉ«£©¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCu2£¨OH£©2CO3$\frac{\underline{\;\;¡÷\;\;}}{\;}$2CuO+H2O+CO2¡ü£»
¹Ê´ð°¸Îª£º£¨1£©¢ÙFe3+    ¢Ú$\stackrel{+3}{Al}$2O3 ¢Û5I  ¢ÜNH4+
£¨2£©¢Ùc   ¢Úa  ¢Ûb  ¢Üd
£¨3£©¢ÙCa£¨OH£©2+CO2¨TCaCO3¡ý+H2O  ¢Ú2Mg+O2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO
¢Û2KMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü£»     ¢ÜCu2£¨OH£©2CO3$\frac{\underline{\;\;¡÷\;\;}}{\;}$2CuO+H2O+CO2¡ü£»

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éѧÉú¶Ô»¯Ñ§ÓÃÓïµÄÊéдºÍÀí½âÄÜÁ¦£¬ÌâÄ¿Éè¼Æ¼È°üº¬¶Ô»¯Ñ§·ûºÅÒâÒåµÄÁ˽⣬ÓÖ¿¼²éÁËѧÉú¶Ô»¯Ñ§·ûºÅµÄÊéд£¬¿¼²éÈ«Ãæ£¬×¢ÖØ»ù´¡£¬ÌâÄ¿ÄѶȽÏÒ×£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø