ÌâÄ¿ÄÚÈÝ
ÈçͼΪËÙÁ¦·Æ²¹Ñª¼ÁµÄ˵Ã÷Êé¡£
£¨1£©ÕáÌÇ(C12H22O6£©ÔÚøµÄ´ß»¯×÷ÓÃÏÂÓëË®×÷ÓÃÖ»Éú³ÉÆÏÌÑÌÇ(C6H12O6 )£¬Ôò1·Ö×ÓÕáÌÇÍêÈ«ÓëË®×÷ÓÿɵÃ______·Ö×ÓÆÏÌÑÌÇ¡£ÈôÏòËÙÁ¦·ÆµÄÈÜÒºÖеμӵâË®£¬½«³ÊÏÖ_______É«¡£
(2)çúçêËáÑÇÌúµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª_______£¬³ÉÈËÿÈÕ1ƬËÙÁ¦·Æ£¬Ã¿ÈյIJ¹ÌúÁ¿Îª_______g¡£
(3)¶¡¶þËáÄÆ(Na2C4H4O4£©ÓëÁòËáÑÇÌú·¢Éú¸´·Ö½â·´Ó¦¿ÉÖÆµÃçúçêËáÑÇÌú£¬Ôò·´Ó¦·½³ÌʽΪ__________¡£
(2)çúçêËáÑÇÌúµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª_______£¬³ÉÈËÿÈÕ1ƬËÙÁ¦·Æ£¬Ã¿ÈյIJ¹ÌúÁ¿Îª_______g¡£
(3)¶¡¶þËáÄÆ(Na2C4H4O4£©ÓëÁòËáÑÇÌú·¢Éú¸´·Ö½â·´Ó¦¿ÉÖÆµÃçúçêËáÑÇÌú£¬Ôò·´Ó¦·½³ÌʽΪ__________¡£
£¨1£©2£»À¶
£¨2£©170£»0.03
£¨3£©Na2C4H4O4+FeSO4==FeC4H4O4+Na2SO4
£¨2£©170£»0.03
£¨3£©Na2C4H4O4+FeSO4==FeC4H4O4+Na2SO4
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÈçͼΪËÙÁ¦·Æ²¹Ñª¼ÁµÄ˵Ã÷Ê飮
£¨1£©ÕáÌÇ£¨C12H22O11£©ÔÚøµÄ´ß»¯×÷ÓÃÏÂÓëË®×÷ÓÃÖ»Éú³ÉÆÏÌÑÌÇ£¨C6H12O6£©£¬Ôò1·Ö×ÓÕáÌÇÈ«ÓëË®×÷Óÿɵà ·Ö×ÓÆÏÌÑÌÇ£®ÈôÏòËÙÁ¦·ÆµÄÈÜÒºÖеμӵâË®£¬½«³ÊÏÖ É«£®
£¨2£©çúçêËáÑÇÌúµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª £¬³ÉÈËÿÈÕ1ƬËÙÁ¦·Æ£¬Ã¿ÈյIJ¹ÌúÁ¿Îª g£®
£¨3£©¶¡¶þËáÄÆ£¨Na2C4H4O4£©ÓëÁòËáÑÇÌú·¢Éú¸´·Ö½â·´Ó¦¿ÉÖÆµÃçúçêËáÑÇÌú£¬Ôò·´Ó¦·½³ÌʽΪ £®
£¨1£©ÕáÌÇ£¨C12H22O11£©ÔÚøµÄ´ß»¯×÷ÓÃÏÂÓëË®×÷ÓÃÖ»Éú³ÉÆÏÌÑÌÇ£¨C6H12O6£©£¬Ôò1·Ö×ÓÕáÌÇÈ«ÓëË®×÷ÓÿɵÃ
£¨2£©çúçêËáÑÇÌúµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª
£¨3£©¶¡¶þËáÄÆ£¨Na2C4H4O4£©ÓëÁòËáÑÇÌú·¢Éú¸´·Ö½â·´Ó¦¿ÉÖÆµÃçúçêËáÑÇÌú£¬Ôò·´Ó¦·½³ÌʽΪ
| ËÙÁ¦·ÆËµÃ÷Êé ¡¾ÕýʽƷÃû¡¿çúçêËáÑÇÌú±¡Ä¤ÒÂÆ¬ ¡¾»¯Ñ§Ê½¡¿çúçêËáÑÇÌúFeC4H4O4 ¡¾ÊÊÓ¦Ö¢¡¿È±ÌúÐÔÆ¶ÑªµÄÔ¤·ÀºÍÖÎÁÆ ¡¾³É·Ö¡¿±¾Æ·Ã¿Æ¬º¬çúçêËáÑÇÌú0.1g ¸¨ÁÏΪ£ºÕáÌÇ¡¢µí·Û¡¢ôÇ»ù¼×ÏËÎ¬ËØµÈ ÈçͼΪËÙÁ¦·Æ²¹Ñª¼ÁµÄ˵Ã÷Ê飮 |
| ËÙÁ¦·ÆËµÃ÷Êé ¡¾ÕýʽƷÃû¡¿çúçêËáÑÇÌú±¡Ä¤ÒÂÆ¬ ¡¾»¯Ñ§Ê½¡¿çúçêËáÑÇÌúFeC4H4O4 ¡¾ÊÊÓ¦Ö¢¡¿È±ÌúÐÔÆ¶ÑªµÄÔ¤·ÀºÍÖÎÁÆ ¡¾³É·Ö¡¿±¾Æ·Ã¿Æ¬º¬çúçêËáÑÇÌú0.1g ¸¨ÁÏΪ£ºÕáÌÇ¡¢µí·Û¡¢ôÇ»ù¼×ÏËÎ¬ËØµÈ |