ÌâÄ¿ÄÚÈÝ

3£®½­Î÷ÊǸöºÃµØ·½£¬ÐÞÐÄÑøÉúÓÐÎÂȪ£¨Â®É½£©¡¢¸»ÑôÉîɽ³ö°×²è£¨×ÊϪ£©¡¢ÃÀ¸þ¼ÑëÈÔ´°×Á«£¨Óà¸É£©£®
£¨1£©Â®É½ÎÂȪˮ¸»º¬Áò¡¢·ú¡¢¹è¡¢¸Æ¡¢¼Ø¡¢Ã¾µÈÔªËØ£¬ÓÉ´Ë¿ÉÅжÏÎÂȪˮÊôÓÚӲˮ£¨ÌӲˮ¡±»ò¡°ÈíË®¡±£©¡®Ó÷ÊÔíË®¿É¼ø¶¨ÎÂȪˮÊǹ¡Ë®»¹ÊÇÈíË®£»
£¨2£©É½ÇåË®ÐãµÄÉú̬×ÊϪ£¬²ú³öµÄ°×²è¾ßÓжÀÌØµÄ·¼Ï㣬ÅݲèʱÓÃÉ´Íø½«²èÒ¶Óë²èË®·ÖÀ룬Ï൱ÓÚ»¯Ñ§ÊµÑé²Ù×÷ÖеĹýÂË£®
£¨3£©Óà¸É°×Á«¸ö´óƤ°×£¬¸»º¬¿óÎïÖÊÈç¸Æ¡¢Áס¢ÌúµÈÎïÖÊ£¬ÕâÀïµÄ¸Æ¡¢Áס¢ÌúÊôÓÚÔªËØ£¨Ìî¡°ÔªËØ¡±»ò¡°Ô­×Ó¡±»ò¡°µ¥ÖÊ¡±»ò¡°Àë×Ó¡±£©£®

·ÖÎö £¨1£©´ÓÎÂȪˮ¸»º¬Áò¡¢·ú¡¢¹è¡¢¸Æ¡¢¼Ø¡¢Ã¾µÈÔªËØ£¬¿É֪ˮÖк¬Óн϶àµÄ¿ÉÈÜÐÔ¸ÆÃ¾»¯ºÏÎËùÒÔÊôÓÚӲˮ£»Ó²Ë®Óë·ÊÔí×÷Óò»ÒׯðÅÝÄ­£¬Òׯð¸¡Ôü£»¶øÈíË®Óë·ÊÔíÒׯðÅÝÄ­È¥·ÖÎö½â´ð£»
£¨2£©´ÓÅݲèʱÓÃÉ´Íø½«²èÒ¶Óë²èË®·ÖÀ룬Ï൱ÓڰѹÌÌåÓëÒºÌå·ÖÀ룬°Ñ¹ÌÌåÓëÒºÌå·ÖÀëµÄ·½·¨ÊǹýÂËÈ¥·ÖÎö½â´ð£»
£¨3£©¸»º¬¿óÎïÖÊÈç¸Æ¡¢Áס¢ÌúµÈÎïÖÊ£¬ÕâÀïµÄ¸Æ¡¢Áס¢Ìú²»ÊÇÒÔµ¥ÖÊ¡¢·Ö×Ó¡¢Ô­×ÓµÈÐÎʽ´æÔÚ£¬¶øÊÇÖ¸ÔªËØ£»

½â´ð ½â£º£¨1£©ÓÉÓÚÎÂȪˮ¸»º¬Áò¡¢·ú¡¢¹è¡¢¸Æ¡¢¼Ø¡¢Ã¾µÈÔªËØ£¬¿É֪ˮÖк¬Óн϶àµÄ¿ÉÈÜÐÔ¸ÆÃ¾»¯ºÏÎËùÒÔÊôÓÚӲˮ£»Ó²Ë®Óë·ÊÔí×÷Óò»ÒׯðÅÝÄ­£¬Òׯð¸¡Ôü£»¶øÈíË®Óë·ÊÔíÒׯðÅÝÄ­£¬ËùÒÔ¿ÉÓ÷ÊÔíË®À´¼ø±ðӲˮºÍÈíË®£»¹Ê´ð°¸Îª£ºÓ²Ë®£»·ÊÔíË®£»
£¨2£©ÅݲèʱÓÃÉ´Íø½«²èÒ¶Óë²èË®·ÖÀ룬Ï൱ÓڰѹÌÌåÓëÒºÌå·ÖÀ룬°Ñ¹ÌÌåÓëÒºÌå·ÖÀëµÄ·½·¨ÊǹýÂË£»¹Ê´ð°¸Îª£º¹ýÂË£»
£¨3£©¸»º¬¿óÎïÖÊÈç¸Æ¡¢Áס¢ÌúµÈÎïÖÊ£¬ÕâÀïµÄ¸Æ¡¢Áס¢Ìú²»ÊÇÒÔµ¥ÖÊ¡¢·Ö×Ó¡¢Ô­×ÓµÈÐÎʽ´æÔÚ£¬¶øÊÇÖ¸ÔªËØ£¬Óë¾ßÌåÐÎ̬Î޹أ»
¹Ê´ð°¸Îª£ºÔªËØ£®

µãÆÀ Éú»î´¦´¦Óл¯Ñ§£¬Ñ§»áÓû¯Ñ§ÖªÊ¶½â¾öÉú»îÖеÄʵ¼ÊÎÊÌ⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
15£®Ì¼Ëá¸ÆÔÚÈÕ³£Éú»îÖеÄÎïÖÊÈ缦µ°¿Ç¡¢±´¿Ç¡¢´óÀíʯ¡¢Ê¯»ÒʯµÈÖдæÔÚ£¬ÓÐºÜ¶àµØ·½ÐèÒªËü£¬Èç²¹¸Æ£¬ÊµÑéÊÒÖÆÈ¡¶þÑõ»¯Ì¼µÈÏÂÃæÊÇÁ½¸öÓ¦ÓÃ̼Ëá¸ÆµÄÀý×Ó£¬Çë¸ù¾ÝÌâÒâ»Ø´ðÏà¹ØÎÊÌ⣮
£¨1£©¹ýÑõ»¯¸Æ¾§Ì壨CaO2•8H2O£©½ÏÎȶ¨£¬³Ê°×É«£¬Î¢ÈÜÓÚË®£¬¹ã·ºÓ¦ÓÃÓÚ»·¾³É±¾ú¡¢Ïû¶¾£®ÒÔ±´¿ÇΪԭÁÏÖÆ±¸CaO2Á÷³ÌÈçÏ£º

ÆøÌåXÊǵÄÃû³ÆÊǶþÑõ»¯Ì¼£»½«¹ýÑõ»¯¸Æ¾§ÌåÓëÈÜÒº·ÖÀëµÄ·½·¨ÊǹýÂË£®¹ýÑõ»¯¸Æ¾§Ì壨CaO2•8H2O£©ÖÐH¡¢OÔªËØµÄÖÊÁ¿±ÈΪ1£º10£®ÈçͼËùʾ£¬·´Ó¦YµÄ·´Ó¦²úÎïÊÇCaO2•8H2O£¬Çëд³ö·´Ó¦Y»¯Ñ§·½³ÌʽCaO+7H2O+H2O2=CaO2•8H2O
£¨2£©Ä³ÑÌÆøÍÑÁòµÄ¹¤ÒÕ²»½öÄÜÏû³ýSO2£¬»¹Äܽ«Æäת»¯ÎªÊ¯¸à£¨CaSO4•2H2O£©µÈ²úÆ·£¬ÊµÏÖ¡°±ä·ÏΪ±¦¡±£®Ö÷ÒªÎïÖÊת»¯¹ØÏµÈçÏ£º

É豸1ÖУ¬Í¨¹ýÅçÁÜË®ÍÑÈ¥ÑÌÆøÖеÄSO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪSO2+H2O¨TH2SO3£®
É豸2ÖУ¬¼ÓÈëCaCO3µÄÄ¿µÄÊǽ«H2SO3ת»¯ÎªCaSO3£®
É豸3ÖУ¬·´Ó¦Ç°ºó»¯ºÏ¼Û·¢Éú¸Ä±äµÄÔªËØÊÇS¡¢O£®
£¨3£©ÎÒ¹úÊÇÊÀ½ç²úú´ó¹ú£®µ«º¬ÁòúȼÉÕÅŷŵĶþÑõ»¯Áò£¬»áÒýÆð¡°ËáÓꡱ£®Îª¼õÉÙ´óÆøÎÛȾ£¬Ä³·¢µç³§²ÉÓÃÁË¡°Ê¯»Ò¹ÌÁò·¨¡±£¬¼´ÔÚÒ»¶¨Ìõ¼þÏÂÏòúÖвôÈëÉúʯ»Ò£¬ÓÃÀ´ÎüÊÕ¶þÑõ»¯Áò£¬ÒÑÖªÕâÒ»¹ý³ÌÖУ¬¸÷ÔªËØµÄ»¯ºÏ¼Û¾ùδ·¢Éú¸Ä±ä£¬Ð´³ö¡°Ê¯»Ò¹ÌÁò·¨¡±µÄ»¯Ñ§·½³ÌʽSO2+CaO=CaSO3£®
£¨4£©¿ÆÑ§¼ÒÔ¤ÑÔ£¬ÇâÄܽ«³ÉΪ21ÊÀ¼ÍµÄÖ÷ÒªÄÜÔ´£¬ÊÔ´ÓÇâÆøµÄÐÔÖÊ·ÖÎöÇâÆø×÷ΪÄÜÔ´µÄÖ÷ÒªÓŵ㣺ÈÈÖµ¸ß£®£¨ÈÎÒ»Ìõ£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø