ÌâÄ¿ÄÚÈÝ

5£®ÑõÆø¡¢Ë®¡¢¶þÑõ»¯Ì¼ÊÇÎÒÃÇÉí±ßÖØÒªµÄ»¯Ñ§ÎïÖÊ£®
£¨1£©ÑõÆø¿ÉÒÔÓÃÓÚÆøº¸Æø¸îµÄÔ­ÒòÊÇÑõÆø¾ßÓÐÖúȼÐÔ£®
£¨2£©Ë®ÊÇÒ»ÖֺܺõÄÈܼÁ£®ÏÂÁм¸ÖÖ¼ÒÓÃÇå½à¼Á¶¼ÊÇÓÃË®×öÈܼÁÅäÖÆ¶ø³ÉµÄ£¬Æä¹¦Äܼ°ÓÐЧ³É·ÖÈçϱíËùʾ£®
 Çå½à¼ÁÃû³Æ  ½à²ÞÁé  »îÑõ²ÊƯ   Æ¯°×¾«
  ¹¦ÄÜ ÓÐЧÇå³ýÎÛ¹¸£¬³ýÒìζ Æ¯Ï´ÒÂÎʹɫ²Ê¸üÏÊÑÞ¿ìËÙÆ¯³ýÒÂÎïÎÛ×Õ
   ÓÐЧ³É·Ö   HCl   H2O2   NaClO
¾Ý±í»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙNaClOÖÐÂÈÔªËØµÄ»¯ºÏ¼ÛΪ+1£®
¢ÚÔÚÊ¢ÓÐÉÙÁ¿¡°»îÑõ²ÊƯ¡±ÒºÌåµÄÊÔ¹ÜÖУ¬¼ÓÉÙÁ¿¶þÑõ»¯ÃÌ£¬¹Û²ìµ½µÄÏÖÏóÊÇÓÐÆøÅݲúÉú£®
¢Û¡°½à²ÞÁ顱Ó롰Ư°×¾«¡±²»ÄÜ»ìÓã®¶þÕßÈô»ìºÏÒײúÉúÓж¾µÄÂÈÆø£¬Í¬Ê±ÓÐÂÈ»¯ÄƺÍË®Éú³É£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2HCl+NaClO¨TNaCl+H2O+Cl2¡ü£®
£¨4£©¡°µÍ̼Éú»î¡±ÓÐÍû³ÉΪеÄʱÉÐÁ÷ÐÐÈ«Çò£®¡°µÍ̼Éú»î¡±ÊÇÖ¸Éú»îÖкÄÓÃÉÙµÄÄÜÁ¿£¬´Ó¶ø½µµÍÌ¼ÌØ±ðÊǶþÑõ»¯Ì¼µÄÅÅ·Å£®ÏÂÁÐÉú»î·½Ê½·ûºÏ¡°µÍ̼Éú»î¡±²¢¿ÉÐеÄÊǢڢܣ¨ÌîÊý×ÖÐòºÅ£©£®
¢Ù½«ºôÎü²úÉúµÄ¶þÑõ»¯Ì¼ÓÃʯ»ÒË®ÎüÊÕ
¢ÚÉÙ¿ªË½¼Ò³µ£¬¶à³Ë×ø¹«¹²½»Í¨¹¤¾ß³öÐÐ
¢Û¹ã·ºÊ¹ÓÃÒ»´ÎÐÔ¿ê×Ó¡¢Ò»´ÎÐÔËÜÁÏ´ü
¢ÜÓõçÓÊ¡¢QQµÈ¼´Ê±Í¨Ñ¶¹¤¾ß£¬ÉÙÓô«Õæ¼°´òÓ¡»ú£®

·ÖÎö £¨1£©¸ù¾ÝÑõÆøµÄ»¯Ñ§ÐÔÖÊ·ÖÎö£»
£¨2£©¸ù¾Ý»¯ºÏÎïÖÐÔªËØµÄ»¯ºÏ¼Û´úÊýºÍΪÁã½øÐзÖÎö£»¹ýÑõ»¯ÇâÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÄÜÉú³ÉÑõÆø£»¸ù¾Ý·´Ó¦ÎïºÍÉú³ÉÎï¼°ÆäÖÊÁ¿Êغ㶨ÂÉ¿ÉÒÔÊéд»¯Ñ§·½³Ìʽ£»
£¨3£©½áºÏÐÅÏ¢¿ÉÖª£¬¡°µÍ̼Éú»î¡±ÊÇÖ¸Éú»îÖкÄÓÃÉÙµÄÄÜÁ¿£¬´Ó¶ø½µµÍÌ¼ÌØ±ðÊǶþÑõ»¯Ì¼µÄÅÅ·Å£¬ÒÔ´ËÀ´½â´ð£®

½â´ð ½â£º£¨1£©ÑõÆø¾ßÓÐÖúȼÐÔ£¬ÓÃÓÚÆøº¸Æø¸î£»
£¨2£©¢ÙNaClOÖУ¬ÄÆÔªËصϝºÏ¼ÛÊÇ+1¼Û£¬ÑõÔªËØµÄ»¯ºÏ¼ÛÊÇ-2¼Û£¬¿ÉÒÔÇó³öÂÈÔªËØµÄ»¯ºÏ¼ÛΪ+1¼Û£®
¢Ú¹ýÑõ»¯ÇâÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÄÜÉú³ÉÑõÆø£®
¢Û¡°½à²ÞÁ顱Ó롰Ư°×¾«¡±»ìºÏÄÜ·¢Éú»¯Ñ§·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2HCl+NaClO=NaCl+H2O+Cl2¡ü£®
£¨3£©ÉÙ¿ªË½¼Ò³µ£¬¶à³Ë×ø¹«¹²½»Í¨¹¤¾ß³öÐм°ÓõçÓÊ¡¢QQµÈ¼´Ê±Í¨Ñ¶¹¤¾ß£¬ÉÙÓô«Õæ´òÓ¡»úµÈ´ëÊ©·ûºÏ¡°µÍ̼Éú»î¡±ÀíÄ¶ø¢Ù¢Û×ö·¨²»¿ÉÈ¡£¬Ö»ÓТڢܷûºÏÌâÒ⣬¹ÊΪ£º¢Ú¢Ü£®
¹Ê´ð°¸Îª£º£¨1£©ÑõÆø¾ßÓÐÖúȼÐÔ£»
£¨2£©¢Ù+1£»¢ÚÓÐÆøÅݲúÉú£»¢Û2HCl+NaClO¨TNaCl+H2O+Cl2¡ü£®
£¨3£©¢Ú¢Ü£®

µãÆÀ ±¾Ì⿼²éÑõÆø¡¢Ë®¡¢¶þÑõ»¯Ì¼µÄÓ¦Óã¬Îª¸ßƵ¿¼µã£¬×¢ÖØ»¯Ñ§Óë»·¾³±£»¤¡¢Éú»îµÄÁªÏµ£¬²àÖØ·ÖÎöÄÜÁ¦¼°ÖªÊ¶×ÛºÏÓ¦ÓÃÄÜÁ¦µÄ¿¼²é£¬×¢ÒâÐÅÏ¢µÄÓ¦Óã¬ÌâÄ¿ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø