ÌâÄ¿ÄÚÈÝ
ʳƷ°²È«ÖÁ¹ØÖØÒª£¬ÎÒÃÇÓ¦¿ÆÑ§ºÏÀíµØÊ¹ÓÃʳƷÌí¼Ó¼Á¡£
£¨1£©ÈËÌå´ÓʳÎïÖÐÉãÈ¡µÄÔªËØ²»×ãʱ£¬¿Éͨ¹ýʳƷÌí¼Ó¼ÁÓèÒÔ²¹³ä£¬ÀýÈ磬¼ÓÌú½´ÓÍ£¬¿ÉÒÔ²¹³äÈËÌåÌúÉãÈë²»×ã¡£ÇëÔÙ¾ÙÒ»Àý
£¨2£©¹ú¼Ò½ûÖ¹ÔÚÃæ·ÛÖÐÌí¼Ó¹ýÑõ»¯¸Æ£¬¹ýÑõ»¯¸ÆµÄ»¯Ñ§Ê½ÎªCaO2£¬ÆäÖиÆÔªËصϝºÏ¼ÛΪ+2£¬ÔòÑõÔªËØµÄ»¯ºÏ¼ÛΪ £»
£¨3£©¹ýÑõ»¯¸Æ²»ÄÜ×öÃæ·ÛÌí¼Ó¼Á£¬µ«¿É×÷Óã³ØÔöÑõ¼Á£¬ËüÓëË®·´Ó¦Éú³ÉÑõÆøºÍÇâÑõ»¯¸Æ£¬Çëд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º £»ÆäÖÐÇâÑõ»¯¸ÆÓÃ;¹ã·º£¬Çëд³öÆäÖÐÒ»Ï ¡£
£¨1£©¼ÓµâʳÑοÉÒÔ²¹³äÈËÌåµâÉãÈë²»×㣨»ò¼Ó¸ÆÒ©¼Á£¬¿ÉÒÔ²¹³äÈËÌ可ÉãÈë²»×㣬ºÏÀí¼´¿É£©£¨2£©£1£¨3£©2CaO2+2H2O=2Ca(OH)2+O2¡ü ¸ÄÁ¼ËáÐÔÍÁÈÀ£¨»òÖкÍËáÐÔ·ÏË®£¬ºÏÀí¼´¿É£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿