ÌâÄ¿ÄÚÈÝ

20£®¶à½Ç¶ÈÈÏʶÎïÖʵı仯£¬ÓÐÖúÓÚÎÒÃǸüºÃµØÀí½â»¯Ñ§ÖªÊ¶£®

£¨1£©´Ó΢¹Û½Ç¶È£º£¨Í¼1Ϊij»¯Ñ§·´Ó¦µÄ΢¹ÛʾÒâͼ£¬¾Ýͼ»Ø´ðÏÂÁÐÎÊÌ⣩
¢Ù΢¹ÛÉÏ¿´£¬¸Ã»¯Ñ§±ä»¯Öз¢Éú¸ù±¾¸Ä±äµÄ΢Á£ÊÇ·Ö×Ó£¨Ñ¡Ìî¡°Ô­×Ó¡±»ò¡°·Ö×Ó£©£»
¢Ú²Î¼Ó·´Ó¦µÄA2ÓëB2Á½ÖÖÎïÖʵķÖ×Ó¸öÊý±ÈΪ1£º1£»
£¨2£©´ÓÄÜÁ¿±ä»¯½Ç¶È£º£¨½èÓÃͼ2×°Ö÷ֱð½øÐÐÏÂÁÐʵÑ飬ÈÏʶÎïÖʱ仯ÖеÄÄÜÁ¿±ä»¯£© 
¢ÙÍùÉÕ±­ÖмÓÈëÒ»¶¨Á¿Éúʯ»Ò»áÒýÆð°×Á×ȼÉÕ£¬´ÓȼÉÕÌõ¼þ·ÖÎö£¬´ËʱÉúʯ»ÒµÄ×÷ÓÃÊÇÉúʯ»ÒÓëË®·´Ó¦·Å³ö´óÁ¿µÄÈÈ£¬Ë®ÎÂÉý¸ß£¬´ïµ½Á˰×Á×µÄ×Å»ðµã£»
¢Ú½«Ò»¶¨Á¿µÄÏÂÁÐijÎïÖÊÈÜÓÚÉÕ±­ÖеÄÀäË®£¬ÆäÖÐÄÜÒýÆð°×Á×ȼÉÕµÄÊÇCD£¨Ñ¡Ìî×ÖĸÐòºÅ£©£®
A£®ÂÈ»¯ÄÆ         B£®ÏõËáï§             C£®Å¨ÁòËá         D£®ÇâÑõ»¯ÄÆ£®

·ÖÎö £¨1£©¸ù¾Ý΢Á£µÄ±ä»¯·ÖÎöÅжϻشð£®
£¨2£©¢Ù¸ù¾ÝÉúʯ»ÒÓëË®µÄ·´Ó¦·ÖÎö»Ø´ð£»
¢ÚÎïÖÊÈÜÓÚÉÕ±­ÖеÄÀäË®£¬ÄÜÒýÆð°×Á×ȼÉÕ£¬ËµÃ÷ÁËÎïÖÊÔÚÈÜÓÚˮʱÄܷųöÈÈÁ¿£¬¾Ý´Ë·ÖÎö£®

½â´ð ½â£º£¨1£©¢Ù΢¹ÛÉÏ¿´£¬ÓÉ΢Á£µÄ±ä»¯¿ÉÖª£¬¸Ã»¯Ñ§±ä»¯Öз¢Éú¸ù±¾¸Ä±äµÄ΢Á£ÊÇ·Ö×Ó£»
¢ÚÓÉ΢Á£µÄ±ä»¯¿ÉÖª£¬²Î¼Ó·´Ó¦µÄA2ÓëB2Á½ÖÖÎïÖʵķÖ×Ó¸öÊý±ÈΪ1£º1£»
£¨2£©¢ÙÍùÉÕ±­ÖмÓÈëÒ»¶¨Á¿Éúʯ»Ò»áÒýÆð°×Á×ȼÉÕ£¬´ÓȼÉÕÌõ¼þ·ÖÎö£¬´ËʱÉúʯ»ÒµÄ×÷ÓÃÊÇ£ºÉúʯ»ÒÓëË®·´Ó¦·Å³ö´óÁ¿µÄÈÈ£¬Ë®ÎÂÉý¸ß£¬´ïµ½Á˰×Á×µÄ×Å»ðµã£®Éúʯ»ÒÓëË®·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£ºCaO+H2O¨TCa£¨OH£©2£®
¢Ú½«Ò»¶¨Á¿µÄÏÂÁÐijÎïÖÊÈÜÓÚÉÕ±­ÖеÄÀäË®£¬ÄÜÒýÆð°×Á×ȼÉÕ£¬ËµÃ÷ÁËÎïÖÊÔÚÈÜÓÚˮʱÄܷųöÈÈÁ¿£¬Å¨ÁòËá¡¢ÇâÑõ»¯ÄÆÔÚÈÜÓÚˮʱÄܷųöÈÈÁ¿£¬ÄÜʹÈÜÒºµÄζÈÉý¸ß£®
¹Ê´ð°¸Îª£º£¨1£©¢Ù·Ö×Ó£¬¢Ú1£º1£»£¨2£©¢ÙÉúʯ»ÒÓëË®·´Ó¦·Å³ö´óÁ¿µÄÈÈ£¬Ë®ÎÂÉý¸ß£¬´ïµ½Á˰×Á×µÄ×Å»ðµã£¬¢ÚCD£®

µãÆÀ ±¾Ìâ´ÓÁ½¸ö·½ÃæÒýµ¼Ñ§ÉúÈÏʶÎïÖʵı仯£¬ÓÐÖúÓÚÎÒÃǸüºÃµØÀí½â¡¢Ó¦Óû¯Ñ§ÖªÊ¶£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
12£®Ä³»¯Ñ§ÐËȤС×éͨ¹ý̽¾¿»î¶¯Ñ§Ï°ºÍÀí½â»¯Ñ§ÖªÊ¶£®ÇëÄãÒ»ÆðÑо¿Ñ§Ï°£¬²¢»Ø´ðÓйØÎÊÌ⣮
Ñо¿Ö÷Ì⣺ˮÈÜÒºÖи´·Ö½â·´Ó¦µÄʵÖÊ
Ïà¹ØÐÅÏ¢£ºÒ»¶¨Ìå»ýµÄÈÜÒºÖУ¬Àë×ÓµÄÊýĿԽ¶à£¬ÆäÀë×ÓµÄŨ¶ÈÔ½´ó£®µçµ¼ÂÊ´«¸ÐÆ÷ÓÃÓÚ²âÁ¿ÈÜÒºµÄµ¼µçÐÔÇ¿Èõ£¬ÄÜ·´Ó³Àë×ÓŨ¶È´óС£®ÏàͬζÈÏÂͬÖÖÈÜÒºµçµ¼ÂÊÔ½´ó£¬Àë×ÓŨ¶ÈÔ½´ó£®
£¨1£©ÊµÑéÒ»£ººãÎÂÌõ¼þÏ£¬ÏòÒ»¶¨Ìå»ýÒ»¶¨Å¨¶ÈµÄÏ¡Ba£¨OH£©2ÈÜÒºÖеμÓ2-3µÎÎÞÉ«·Ó̪ÊÔÒº£¬²åÈëµçµ¼ÂÊ´«¸ÐÆ÷£¬È»ºóµÎ¼ÓÏ¡ÁòËᣬ²âµÃÈÜÒºµÄµçµ¼Âʱ仯ÈçͼÖм×ÇúÏßËùʾ£®
¢Ùд³öBa£¨OH£©2ÓëH2SO4·´Ó¦µÄ»¯Ñ§·½³ÌʽBa£¨OH£©2+H2SO4=BaSO4¡ý+2H2O£®
¢Ú¼×ÇúÏßMµãʱ»ìºÏÒºÌå³ÊÎÞÉ«£»
¢Ûͨ¹ý¶Ô¼×ÇúÏߵķÖÎö£¬ÏÂÁÐ˵·¨´íÎóµÄÊÇC£¨ÌîÐòºÅ£©£®
A£®MµãǰÇúÏßÏ»¬µÄ¹ý³ÌÖУ¬H+ºÍOH-½áºÏ³ÉH2O£¬Ba2+ºÍSO42-½áºÏ³ÉBaSO4
B£®MµãʱÀë×ÓŨ¶È¼¸ºõΪÁã
C£®MµãºóÈÜÒºµçµ¼ÂÊÖð½¥Ôö´ó£¬½öÓÉÓÚÈÜÒºÖÐH+ÔÚÖð½¥Ôö´ó
£¨2£©ÊµÑé¶þ£ººãÎÂÌõ¼þÏ£¬ÏòµÈÁ¿Í¬Å¨¶ÈµÄÏ¡Ba£¨OH£©2ÈÜÒºÖеμÓ2-3µÎÎÞÉ«·Ó̪ÊÔÒº£¬²åÈëµçµ¼ÂÊ´«¸ÐÆ÷£¬È»ºóµÎ¼ÓÏ¡Na2SO4ÈÜÒº£¬²âµÃÈÜÒºµÄµçµ¼Âʱ仯ÈçÉÏͼÒÒÇúÏßËùʾ£®
¢Ùͨ¹ý¶ÔÒÒÇúÏߵķÖÎö£¬ÏÂÁÐ˵·¨´íÎóµÄÊÇA£¨ÌîÐòºÅ£©£®
A£®¿ªÊ¼ÖÁÍêÈ«·´Ó¦¹ý³ÌÖУ¬µçµ¼ÂʼõС£¬ÈÜÒºÓɺìÉ«Öð½¥±äΪÎÞÉ«
B£®µçµ¼ÂÊϽµµ½×îµÍµãʱÈÔÈ»½Ï´ó£¬±íÃ÷ÈÜÒºÖл¹´æÔڽ϶àÀë×Ó
C£®Õû¸öʵÑé¹ý³ÌÖУ¬ÈÜÒºÖÐNa+ÊýĿһֱÔö´ó
¢ÚNµãʱ£¬ÈÜÒºÖк¬ÓеÄÀë×ÓÊÇNa+¡¢OH-¡¢SO42-£¨ÌîÀë×Ó·ûºÅ£©£®
¢Ûͨ¹ý±È½Ï·ÖÎö£¬½áºÏÒÑѧ֪ʶ¿ÉÖª£¬ÈÜÒºÖи´·Ö½â·´Ó¦µÄʵÖÊÊDzÎÓë·´Ó¦µÄÀë×Ó£¬½áºÏÉú³ÉÁ˳Áµí¡¢ÆøÌå»òË®£¬µ¼ÖÂÆäŨ¶È¼õС£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±£©£®
£¨3£©ÍØÕ¹£º¢ÙÇë¸ù¾ÝʾÀý·ÂдÀë×Ó·½³Ìʽ£®
ʾÀýAgNO3+NaCl=AgCl¡ý+NaNO3Àë×Ó·½³Ìʽ£ºAg++Cl-=AgCl¡ý
·Âд£ºBaCl2+Na2SO4=BaSO4¡ý+2NaClÀë×Ó·½³Ìʽ£ºBa2++SO42-=BaSO4¡ý£®
¢ÚÏòÒ»¶¨Á¿±¥ºÍ³ÎÇåʯ»ÒË®ÖгÖÐøÍ¨Èë¹ýÁ¿µÄCO2ÆøÌ壬ÈÜÒºÏȱä»ë×Ǻó»ë×ÇÖð½¥Ïûʧ£®ÇëÍÆ²â´Ë¹ý³ÌµÄÈÜÒºÖÐCa2+µÄŨ¶È±ä»¯Çé¿öÏȼõСºóÔö´ó£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø