ÌâÄ¿ÄÚÈÝ

СÃ÷ͬѧÀûÓÃÒÔϲÄÁÏ×ÔÖÆËáÌð¿É¿ÚµÄÆûË®¡£

²ÄÁÏ:1Æ¿(500 mL)´¿¾»Ë®¡¢5gÕáÌÇ(C12H22O11)¡¢1. 5 gСËÕ´ò(NaHCO3)¡¢1.5 gÄûÃÊËá(C6H8O7)¡£

ÖÆ±¸¹ý³ÌÈçÏÂͼËùʾ:

ÒÑÖª:СËÕ´òÓëÄûÃÊËá·¢ÉúµÄ·´Ó¦Îª3NaHCO3 +C6H8O7=C6H5O7Na3+3H2O+3CO2¡ü

£¨1£©NaHCO3ÓÉ___________ÖÖÔªËØ×é³É£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª_________¡£

£¨2£©ÕáÌÇÖи÷ÔªËØµÄÖÊÁ¿±ÈΪ____________________¡£

£¨3£©ÄûÃÊËáÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊýΪ________________¡£

£¨4£©¼ÓÈëÄûÃÊËáºó£¬Á¢¼´Ðý½ôÆ¿¸ÇµÄÔ­ÒòÊÇ______________¡£

£¨5£©×ÔÖÆÆûË®µÄÈÜÖÊÓÐC6H5O7Na3¡¢CO2¡¢C12H22O11ºÍ_______________(Ìѧʽ)¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

»¹Ô­Ìú·ÛÊǽṹÊèËɵĵ¥ÖÊÌú£¬ÊÇÖØÒªµÄ¹¤ÒµÔ­ÁÏ¡£

I£®ÎïÖÊÖÆ±¸¡£»¹Ô­Ìú·ÛµÄijÖÖÖÆ±¸¹¤ÒÕÁ÷³ÌÈçÏ£º

£¨1£©¡°×ª»¯¡±Ê±Î¶ÈÐè¿ØÖÆÔÚ35¡æÒÔÏ£¬·ÀÖ¹ÊÜÈÈ·Ö½âµÄÎïÖÊÊÇ_____¡£

£¨2£©¡°¸ÉÔ¹ý³ÌÖÐÓÐÉÙÁ¿µÄFeCO3ת»¯ÎªFeOOHºÍCO2£¬´ËʱÓëFeCO3·´Ó¦µÄÎïÖÊÓÐ_____£¨Ìѧʽ£©

£¨3£©FeCO3ºÍ FeOOHÔÚ¿ÕÆøÖбºÉÕת»¯ÎªFe2O3£¬FeOOHת»¯ÎªFe2O3µÄ·´Ó¦ÀàÐÍÊÇ_____¡£Ð´³öFe2O3ÔÚ¸ßÎÂÌõ¼þÏÂÓë̼£¨C£©·´Ó¦Éú³ÉFeºÍCO2µÄ»¯Ñ§·½³Ìʽ£º_____¡£

¢ò£®³É·ÖÑо¿¡£¡°Å¯±¦±¦¡±Ò»°ãÓÉ»¹Ô­Ìú·Û¡¢»îÐÔÌ¿ºÍÂÈ»¯ÄƵÈ×é³É¡£

£¨ÊµÑéÄ¿µÄ£©²â¶¨Î´¿ªÆôµÄ¡°Å¯±¦±¦¡±ÖÐÌúµÄÖÊÁ¿·ÖÊý¡£

£¨ÊµÑé¹ý³Ì£©ÈçͼÎåËùʾ£¬¼×ͬѧ³ÆµÃ·´Ó¦Ç°×ÜÖÊÁ¿Îª85g£¬´ò¿ª»îÈû´ýÏ¡ÑÎËáÈ«²¿µÎÈëºóÁ¢¼´¹Ø±Õ»îÈû¡£×¶ÐÎÆ¿ÄÚµÄÏÖÏóÓУº¹ÌÌåÖð½¥¼õÉÙ£¬_____¡£·´Ó¦Íê±Ïºó²âµÃ×¶ÐÎÆ¿ºÍ·´Ó¦ºó»ìºÏÎïµÄ×ÜÖÊÁ¿Îª84.8g¡£

£¨ÆÀ¼Û·´Ë¼£©

£¨1£©ÒÒͬѧÈÏΪ¼×ͬѧ·½°¸Îó²î½Ï´ó£¬ÓÚÊÇÉè¼ÆÈçͼÁùµÄ·½°¸¡£¼×ͬѧ·½°¸Îó²î½Ï´óµÄÔ­ÒòÊÇ_____¡£

£¨2£©±ûͬѧÈÏΪÒÒͬѧ·½°¸¼´Ê¹²Ù×÷ÎÞʧÎ󣬲âÁ¿½á¹ûÈÔ»áÆ«´ó£¬Ô­ÒòÊÇ_____¡£

£¨3£©±ûͬѧÉè¼ÆÁËͼÆßµÄʵÑé×°Öá£ÀûÓøÃ×°ÖÃʵÑéʱ£¬ÔÚÆøÃÜÐÔÁ¼ºÃµÄǰÌáÏ£¬Èç¹ûÍù×¶ÐÎÆ¿ÖÐ×¢ÈëµÄÏ¡ÑÎËáÌå»ýΪV1mL£¬µÈ³ä·Ö·´Ó¦²¢ÇÒ´ý×°ÖÃÀäÈ´ºó£¬¹Û²ìÓÒ²à×¢ÉäÆ÷¶ÁÊý‰ˆ¼ÓV2mL£®ÊµÑéÌõ¼þÏÂÇâÆøÃܶÈΪ d g/mL£®ÔòÑùÆ·ÖÐÌúµÄÖÊÁ¿·ÖÊýΪ_____¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø