ÌâÄ¿ÄÚÈÝ
ͬѧÃÇÓÃNa2CO3ÈÜÒººÍŨHClÀ´Ñо¿¼òÒ×Ãð»ðÆ÷µÄ·´Ó¦ÔÀíʱ£¬¶Ô·ÏÒºµÄ³É·Ö½øÐÐ̽¾¿¡£
[ÍÆÀí¼ÙÉè]
ÉÏÊöÁ½ÖÖÎïÖÊ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ £¬ÓÉ´ËÍÆ²â³ö·ÏÒºÖÐÒ»¶¨ÓÐNaCl£¬¿ÉÄÜÓÐNa2CO3»òÑÎËá¡£
[ʵÑé̽¾¿]
(Ò»)È·¶¨·ÏÒºÖÐÊÇ·ñº¬ÓÐÑÎËá
£¨1£©Ñ¡ÔñÊÔ¼Á£º¸ù¾ÝÑÎËáµÄ»¯Ñ§ÐÔÖÊ£¬Í¬Ñ§ÃÇÑ¡ÓÃÁËÈçͼËùʾµÄÎåÖÖÎïÖÊ£¬ÆäÖÐÎïÖÊxÊÇËá¼îָʾ¼ÁÖÐµÄ ÈÜÒº¡£
£¨2£©ÊµÑéÑéÖ¤£ºÄ³Í¬Ñ§Ïò·ÏÒºÖмÓÈëÉÙÁ¿µÄþ·Û£¬¹Û²ìµ½È·¶¨·ÏÒºÖÐÒ»¶¨Ã»ÓÐÑÎËá¡£
(¶þ)È·¶¨·ÏÒºÖÐÊÇ·ñº¬ÓÐNa2CO3
ijͬѧѡÓà ²â³ö·ÏÒºµÄpH=l0£¬È·¶¨·ÏÒºÖÐÒ»¶¨º¬ÓÐNa2CO3¡£
(Èý)´¦Àí·ÏÒº£¬»ØÊÕÀûÓÃ
Óû´Ó·ÏÒºÖеõ½´¿¾»µÄNaCl£¬ÇëÍê³ÉÈçÏÂʵÑé·½°¸Éè¼Æ¡£
| ·½°¸ | ¼ÓÈëÊÔ¼Á | ·ÖÀë·½·¨ | ·½°¸ÆÀ¼Û |
|
| ÊÊÁ¿Ca(NO3)2ÈÜÒº | ¹ýÂË¡¢Õô·¢½á¾§ | ²»¿ÉÐУ¬ÀíÓÉÊÇ
|
|
| ¹ýÁ¿µÄ | Õô·¢½á¾§ | ¿ÉÐÐ |
[ÍÆÀí¼ÙÉè]
Na2CO3+2HCl= 2NaCl+H2O+CO2¡ü(2·Ö)
[ʵÑé̽¾¿]
(Ò»)¢ÅʯÈï(1·Ö)
¢ÆÎÞÆøÅݲúÉú(»òÎÞÏÖÏó»òÎޱ仯) (1·Ö)
(¶þ)pHÊÔÖ½(»òpH¼Æ) (1·Ö)
| ·½°¸ | ¼ÓÈëÊÔ¼Á | ·ÖÀë·½·¨ | ·½°¸ÆÀ¼Û |
| Ò» |
|
| Òý½øÐÂÔÓÖÊ(»òÓÐNaNO3Éú³É»òÒý½øNO3¡ª¸ùÀë×Ó)(1·Ö) |
| ¶þ | ÑÎËá(»òÏ¡HCl»òHCl)(1·Ö) |
|
|
½âÎö:ÂÔ
ͬѧÃÇÓÃNa2CO3ÈÜÒººÍŨHClÀ´Ñо¿¼òÒ×Ãð»ðÆ÷µÄ·´Ó¦ÔÀíʱ£¬¶Ô·ÏÒºµÄ³É·Ö½øÐÐ̽¾¿£®
ÍÆÀí¼ÙÉè
ÉÏÊöÁ½ÖÖÎïÖÊ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£¬ÓÉ´ËÍÆ²â³ö·ÏÒºÖÐÒ»¶¨ÓÐNaCl£¬¿ÉÄÜÓÐNa2CO3»òHCl
ʵÑé̽¾¿
£¨Ò»£©È·¶¨·ÏÒºÖÐÊÇ·ñº¬ÓÐÑÎËá
£¨1£©Ñ¡ÔñÊÔ¼Á£º¸ù¾ÝÑÎËáµÄ»¯Ñ§ÐÔÖÊ£¬Í¬Ñ§ÃÇ¿ÉÑ¡ÓÃʯÈï¡¢Mg¡¢______¡¢______¡¢______£¨²»Í¬Àà±ðµÄ»¯ºÏÎ£®
£¨2£©ÊµÑéÑéÖ¤£ºÄ³Í¬Ñ§Ïò·ÏÒºÖмÓÈëÉÙÁ¿µÄþ·Û£¬¹Û²ìµ½·ÏÒºÖÐ______£¬È·¶¨Ò»¶¨Ã»ÓÐÑÎËᣮ
£¨¶þ£©È·¶¨·ÏÒºÖÐÊÇ·ñº¬ÓÐNa2CO3
ijͬѧѡÓÃ______²â³ö·ÏÒºµÄpH=l0£¬È·¶¨·ÏÒºÖÐÒ»¶¨º¬ÓÐNa2CO3£®
£¨Èý£©´¦Àí·ÏÒº£¬»ØÊÕÀûÓÃ
Óû´Ó·ÏÒºÖеõ½´¿¾»µÄNaCl£¬ÇëÍê³É¶ÔÏÂÁÐʵÑé·½°¸Éè¼ÆµÄÆÀ¼Û£®
| ·½°¸ | ¼ÓÈëÊÔ¼Á | ·ÖÀë·½·¨ | ·½°¸ÆÀ¼Û £¨Ðлò²»ÐУ¬²¢ËµÃ÷ÀíÓÉ£© |
| Ò» | ÊÊÁ¿Ca£¨NO3£©2ÈÜÒº | ¹ýÂË¡¢Õô·¢½á¾§ | ______ |
| ¶þ | ¹ýÁ¿µÄHClÈÜÒº | Õô·¢½á¾§ | ______ |