ÌâÄ¿ÄÚÈÝ
Çë¸ù¾ÝÌâĿҪÇ󻨴ðÏÂÁÐÎÊÌâ¡£
(1)ͼΪÍÐÅÌÌìÆ½£¬Ê¹ÓÃÍÐÅÌÌìÆ½³ÆÁ¿Î´ÖªÖÊÁ¿ÎïÆ·ÖÊÁ¿µÄÕýÈ·²Ù×÷˳ÐòΪ (ÌîÐòºÅ)_____
¢Ùµ÷ÓÎÂë¢Ú·Å³ÆÁ¿Ö½¢Û³ÆÁ¿Îï·Å×óÅ̢ܵ÷Áãµã¢Ý¼ÓÖÊÁ¿´óµÄíÀÂë¢Þ¼ÓÖÊÁ¿Ð¡µÄíÀÂë
A£®¢Ù¢Ú¢Û¢Ü¢Ý¢ÞB£®¢Ü¢Ú¢Þ¢ÙC£®¢Ü¢Ý¢Þ¢Ù¢Ú¢Û
![]()
(2)ÔÚСÉÕ±ÖмÓÈëÁòËáÍÈÜÒººó£¬¼ÓÈëÌú¶¤£¬³ÆÁ¿×ÜÖÊÁ¿Îªm1£¬·¢Éú·´Ó¦µÄʵÑéÏÖÏóΪ___£¬___£»¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____£»·´Ó¦Ò»¶Îʱ¼äºó£¬ÔÙ³ÆÁ¿Ð¡ÉÕ±¼°ÉÕ±ÄÚÎïÖʵÄ×ÜÖÊÁ¿Îªm2£¬Ôòm1£½m2
(3)ÈçͼװÖÃÖУ¬³ÆÁ¿Ð¡ÉÕ±ÖÐËùÓÐÎïÖʵÄÖÊÁ¿m3£¬È»ºó½«Ð¡ÉÕ±ÖеÄ̼Ëá¸ÆÓëÑÎËáÍêÈ«»ìºÏ£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____¡£·´Ó¦·¢ÉúÁËÒ»¶Îʱ¼äºó£¬ÔÙ³ÆÁ¿Ð¡ÉÕ±¼°ÉÕÆ¿ÄÚÎïÖʵÄ×ÜÖÊÁ¿Îªm4£¬Ôò (Ìî¡°£½¡±¡°£¾¡±¡°£¼¡±)m3_____m4£¬Ôì³ÉÕâÑù´íÎó½áÂÛÊÇÒòΪʵÑé×°ÖóöÏÖÁËÎÊÌ⣬ÇëÄãд³öÒ»Ìõ¸Ä½ø¸ÃʵÑéµÄ·½·¨_____
![]()
(4)ÔÚ2A+5B£½4C+6DµÄ·´Ó¦ÖУ¬C¡¢DÏà¶Ô·Ö×ÓÖÊÁ¿Ö®±ÈΪ15£º9£¬Èô1.7gAÓëBÍêÈ«·´Ó¦Éú³É3gC£¬ÔòBºÍCµÄÖÊÁ¿±ÈΪ_____£¬AºÍBµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ö®±ÈΪ_____¡£
ÏÂÁгýÔÓ·½·¨ÖУ¬ÄܴﵽĿµÄÊÇ(¡¡¡¡)
Ñ¡ Ïî | ÎïÖÊ(À¨ºÅÄÚΪÔÓÖÊ) | ³ýÈ¥ÔÓÖʵķ½·¨ |
A | C(CuO) | ¸ô¾ø¿ÕÆø¼ÓÇ¿ÈÈ |
B | CaO(CaCO3) | ¼ÓÏ¡ÑÎËá¡¢¹ýÂË |
C | NaOH(Na2CO3) | ¼ÓÈëÊÊÁ¿µÄCaCl2ÈÜÒº£¬²¢¹ýÂË |
D | CuSO4ÈÜÒº(H2SO4) | ¼Ó×ãÁ¿Ñõ»¯Í·ÛÄ©£¬¹ýÂË |
A. A B. B C. C D. D