ÌâÄ¿ÄÚÈÝ

14£®È¼ÉÕÊÇÈËÀà×îÔçÀûÓõĻ¯Ñ§·´Ó¦Ö®Ò»£®
£¨1£©ÏÂÃæÊÇһЩ³£ÓõÄÃð»ð·½·¨µÄÊÂÀý£º
¢ÙϨÃð¾Æ¾«µÆÊ±£¬ÓõÆÃ±¸ÇÃ𣻢ÚϨÃðÈ¼ÆøÔî»ðÑæÊ±£¬¹Ø±Õ·§ÃÅ£»¢ÛÓ͹ø×Å»ðʱ£¬Óùø¸Ç¸ÇÃð£»
¢ÜÉ­ÁÖ×Å»ðʱ£¬½«´ó»ðÂûÑÓÏß·ǰµÄһƬÊ÷ľ¿³µô£»¢Ý·¿ÎÝ×Å»ðʱ£¬ÓøßѹˮǹÃð»ð£®
ÇëÄã´ÓÃð»ðÔ­Àí½Ç¶È£¬Ñ¡ÔñÒ»ÖÖ·ÖÀà±ê×¼½øÐзÖÀࣺ
·ÖÀà±ê×¼¸ô¾øÑõÆø£¨»òÇå³ý¸ôÀë¿ÉȼÎï»ò½µÎµ½×Å»ðµãÒÔÏ£©°üÀ¨ÊÂÀý¢Ù¢Û£¨»ò¢Ú¢Ü»ò¢Ý£© £¨ÌîÐòºÅ£©
£¨2£©ÆøÌå´ò»ð»úÖг£Óö¡Í飨C4H10£©×öȼÁÏ£¬¶¡ÍéÓë¼×ÍéÍêȫȼÉÕ²úÎïÏàͬ£®Çëд³ö¶¡ÍéÍêȫȼÉյĻ¯Ñ§·½³Ìʽ2C4H10+13O2$\frac{\underline{\;µãȼ\;}}{\;}$8CO2+10H2O£®

·ÖÎö ¸ù¾ÝÒÑÓеÄÃð»ðµÄÔ­Àí½øÐзÖÎö½â´ð¼´¿É£¬¸ù¾Ý·´Ó¦ÎïºÍÉú³ÉÎïÊéд·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬¾Ý´Ë½â´ð£®

½â´ð ½â£º£¨1£©¢ÙϨÃð¾Æ¾«µÆÊ±£¬ÓõÆÃ±¸ÇÃð£¬ÀûÓõÄÊǸô¾øÑõÆø£»¢ÚϨÃðÈ¼ÆøÔî»ðÑæÊ±£¬¹Ø±Õ·§ÃÅ£¬ÀûÓõÄÔ­ÀíÊÇÒÆ×ß¿ÉȼÎ¢ÛÓ͹ø×Å»ðʱ£¬Óùø¸Ç¸ÇÃð£¬ÀûÓõÄÔ­ÀíÊǸô¾øÑõÆø£»¢ÜÉ­ÁÖ×Å»ðʱ£¬½«´ó»ðÂûÑÓÏß·ǰµÄһƬÊ÷ľ¿³µô£®ÀûÓõÄÔ­ÀíÊÇÒÆ×ß¿ÉȼÎ¢Ý·¿ÎÝ×Å»ðʱ£¬ÓøßѹˮǹÃð»ðÀûÓõÄÔ­ÀíÊǽµµÍζȵ½¿ÉȼÎïµÄ×Å»ðµãÒÔÏ£¬¹ÊÌ¸ô¾øÑõÆø£¬¢Ù¢Û£¨»òÇå³ý¸ôÀë¿ÉȼÎڢܡ¢»ò½µÎµ½×Å»ðµãÒÔÏ ¢Ý£©£»
£¨2£©¶¡ÍéºÍÑõÆø·´Ó¦Éú³É¶þÑõ»¯Ì¼ºÍË®£¬¹ÊÌ2C4H10+13O2$\frac{\underline{\;µãȼ\;}}{\;}$ 8CO2+10H2O£®

µãÆÀ ±¾Ì⿼²éµÄÊÇÃð»ðÔ­ÀíµÄÓ¦ÓúÍÓйط´Ó¦»¯Ñ§·½³ÌʽµÄÊéд£¬Íê³É´ËÌ⣬¿ÉÒÔÒÀ¾ÝÒÑÓеÄ֪ʶ½øÐУ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø