Question

15£®Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£®
£¨1£©ÌúË¿ÔÚÑõÆøÖÐȼÉÕ3Fe+2O₂$\frac{\underline{\;µãȼ\;}}{\;}$Fe₃O₄£»
£¨2£©µç½âË®2H₂O$\frac{\underline{\;ͨµç\;}}{\;}$2H₂¡ü+O₂¡ü£»
£¨3£©¹ýÑõ»¯Çâ·Ö½âÖÆÈ¡ÑõÆø2H₂O₂$\frac{\underline{\;MnO_2\;}}{\;}$2H₂O+O₂¡ü£»
£¨4£©´óÀíʯÓëÏ¡ÑÎËá·´Ó¦CaCO₃+2HCl=CaCl₂+H₂O+CO₂¡ü£»
£¨5£©Ì¼²»ÍêȫȼÉÕ2C+O₂$\frac{\underline{\;µãȼ\;}}{\;}$2CO£»
£¨6£©¼ÓÈÈÂÈËá¼ØÖÆÈ¡ÑõÆø2KClO₃$\frac{\underline{MnO_2}}{¡÷}$2KCl+3O₂¡ü£»
£¨7£©ÌúÓëÁòËáÍ­·´Ó¦Fe+CuSO₄=FeSO₄+Cu£®

Answer 1

·ÖÎö £¨1£©¸ù¾ÝÌúË¿ºÍÑõÆøÔÚµãȼµÄÌõ¼þÏÂÉú³ÉËÄÑõ»¯ÈýÌú½øÐзÖÎö£»
£¨2£©¸ù¾ÝË®ÔÚͨµçµÄÌõ¼þÏÂÉú³ÉÇâÆøºÍÑõÆø½øÐзÖÎö£»
£¨3£©¸ù¾Ý¹ýÑõ»¯ÇâÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÉú³ÉË®ºÍÑõÆø½øÐзÖÎö£»
£¨4£©¸ù¾Ý̼Ëá¸ÆºÍÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼½øÐзÖÎö£»
£¨5£©¸ù¾Ý̼ºÍÑõÆøÔÚ²»ÍêȫȼÉÕµÄÌõ¼þÏÂÉú³ÉÒ»Ñõ»¯Ì¼½øÐзÖÎö£»
£¨6£©¸ù¾ÝÂÈËá¼ØÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÉú³ÉÂÈ»¯¼ØºÍÑõÆø½øÐзÖÎö£»
£¨7£©¸ù¾ÝÌúºÍÁòËáÍ­·´Ó¦Éú³ÉÁòËáÑÇÌúºÍÍ­½øÐзÖÎö£®

½â´ð ½â£º£¨1£©ÌúË¿ºÍÑõÆøÔÚµãȼµÄÌõ¼þÏÂÉú³ÉËÄÑõ»¯ÈýÌú£¬»¯Ñ§·½³ÌʽΪ£º3Fe+2O₂$\frac{\underline{\;µãȼ\;}}{\;}$Fe₃O₄£»
£¨2£©Ë®ÔÚͨµçµÄÌõ¼þÏÂÉú³ÉÇâÆøºÍÑõÆø£¬»¯Ñ§·½³ÌʽΪ£º2H₂O$\frac{\underline{\;ͨµç\;}}{\;}$2H₂¡ü+O₂¡ü£»
£¨3£©¹ýÑõ»¯ÇâÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÉú³ÉË®ºÍÑõÆø£¬»¯Ñ§·½³ÌʽΪ£º2H₂O₂$\frac{\underline{\;MnO_2\;}}{\;}$2H₂O+O₂¡ü£»
£¨4£©Ì¼Ëá¸ÆºÍÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬»¯Ñ§·½³ÌʽΪ£ºCaCO₃+2HCl=CaCl₂+H₂O+CO₂¡ü£»
£¨5£©Ì¼ºÍÑõÆøÔÚ²»ÍêȫȼÉÕµÄÌõ¼þÏÂÉú³ÉÒ»Ñõ»¯Ì¼£¬»¯Ñ§·½³ÌʽΪ£º2C+O₂$\frac{\underline{\;µãȼ\;}}{\;}$2CO£»
£¨6£©ÂÈËá¼ØÔÚ¶þÑõ»¯Ã̵Ĵ߻¯×÷ÓÃÏÂÉú³ÉÂÈ»¯¼ØºÍÑõÆø£¬»¯Ñ§·½³ÌʽΪ£º2KClO₃$\frac{\underline{MnO_2}}{¡÷}$2KCl+3O₂¡ü£»
£¨7£©ÌúºÍÁòËáÍ­·´Ó¦Éú³ÉÁòËáÑÇÌúºÍÍ­£¬»¯Ñ§·½³ÌʽΪ£ºFe+CuSO₄=FeSO₄+Cu£®
¹Ê´ð°¸Îª£º£¨1£©3Fe+2O₂$\frac{\underline{\;µãȼ\;}}{\;}$Fe₃O₄£»
£¨2£©2H₂O$\frac{\underline{\;ͨµç\;}}{\;}$2H₂¡ü+O₂¡ü£»
£¨3£©2H₂O₂$\frac{\underline{\;MnO_2\;}}{\;}$2H₂O+O₂¡ü£»
£¨4£©CaCO₃+2HCl=CaCl₂+H₂O+CO₂¡ü£»
£¨5£©2C+O₂$\frac{\underline{\;µãȼ\;}}{\;}$2CO£»
£¨6£©2KClO₃$\frac{\underline{MnO_2}}{¡÷}$2KCl+3O₂¡ü£»
£¨7£©Fe+CuSO₄=FeSO₄+Cu£®

µãÆÀ ÔÚ½â´ËÀàÌâʱ£¬Ê×ÏÈ·ÖÎöÓ¦ÓõÄÔ­Àí£¬È»ºóÕÒ³ö·´Ó¦Îï¡¢Éú³ÉÎ×îºó½áºÏ·½³ÌʽµÄÊéд¹æÔòÊéд·½³Ìʽ£®