ÌâÄ¿ÄÚÈÝ
¼¦µ°¿ÇµÄÖ÷Òª³É·ÖÊÇ̼Ëá¸Æ£¬ÎªÁ˲ⶨij¼¦µ°¿ÇÖÐ̼Ëá¸ÆµÄº¬Á¿£¬Ð¡ÈºÍ¬Ñ§½øÐÐÁËÈçÏÂʵÑ飺½«¼¦µ°¿ÇÏ´¾»¡¢¸ÉÔï²¢µ·Ëéºó£¬³ÆÈ¡10g·ÅÔÚÉÕ±ÀȻºóÍùÉÕ±ÖмÓÈë×ãÁ¿µÄÏ¡ÑÎËá90g£¬³ä·Ö·´Ó¦ºó£¬³ÆµÃÉÕ±ÖÐÎïÖʵÄ×ÜÖÊÁ¿Îª97.8g¡££¨¼ÙÉ輦µ°¿ÇÖÐµÄÆäËûÎïÖʲ»ÓëÑÎËá·´Ó¦£©
£¨1£©²úÉú¶þÑõ»¯Ì¼ÆøÌå g¡£
£¨2£©¼ÆËã10g¸Ã¼¦µ°¿ÇÖÐ̼Ëá¸ÆµÄÖÊÁ¿£¬ÒªÇóд³öÍêÕûµÄ½âÌâ²½Öè¡£
(1)2.2 (2·Ö)
(2)(¡°µ¥Î»¡±È«¶Ô¸ø1·Ö£¬¡°µ¥Î»¡±ÓÐ´í²»¸ø·Ö¡£»¯Ñ§·½³Ìʽȫ¶Ô¸ø1·Ö£¬ÓÐ´í²»¸ø·Ö¡£´ËСÌâ²ÉÓ÷ֲ½¸ø·Ö·¨£¬¼Ó¡°µ¥Î»¡±·Ö¹²6·Ö)
½â£ºÉè10g¸Ã¼¦µ°¿ÇÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx (0.5·Ö)
CaCO3+2HCl== CaCl2+ H2O + CO2 ¡ü (1·Ö)
100 44
x 2.2g (1·Ö)
=
(1·Ö)
x =5g (1·Ö)
´ð£º10g¸Ã¼¦µ°¿ÇÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îª5g¡£ (0.5·Ö)