ÌâÄ¿ÄÚÈÝ

1£®2015Äê4ÔÂ6ÈÕ¸£½¨ÕÄÖݹÅÀ×ʯ»¯·¢ÉúPX±¬Õ¨£¬ÒýÆðÃñÖڿֻţ¬×ÊÁÏÃèÊö¡°PX¡±Îª¡°µÍ¶¾»¯ºÏÎ£¬Ïò¹úÈ˽ÒʾÁË×ðÖØÊÂʵµÄ¿ÆÑ§Ì¬¶È£¬PXÊÇ¡°¶Ô¶þ¼×±½¡±»¯Ñ§Ê½ÎªC8H10£¬ÆäÏà¹ØÐÔÖÊÈçÏ£º
¢ÙÎÞɫ͸Ã÷ÒºÌ壬´øÓз¼ÏãÆøÎ¶¢ÚÈܵã13.2¡æ¡¢·Ðµã138.5¡æ¢ÛÃܶÈ0.86g/cm3¢Ü¿Éȼ
¢ÝÓлӷ¢ÐÔ£¬µ«±ÈÆûÓ͵͢ÞÓö»ð¿É±¬Õ¨£¬µ«±¬Õ¨ÐÔ±ÈÆûÓ͵Í
¢ßµÍ¶¾£¬¶¾ÐÔÓëÆûÓÍÏ൱£®
¸ù¾ÝÉÏÊöÐÅÏ¢£®ÇëÄã»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÉÏÊöÖÐÊôÓÚPXÎïÀíÐÔÖʵÄÊÇ£¨ÌîÊý×ÖÐòºÅ£©¢Ù¢Ú¢Û¢Ý£»
£¨2£©¡°PX¡±ÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊýΪ90.6%£¨¾«È·µ½0.1% £© 21.2gµÄPXÓë25.6gg
¼×Í麬̼Á¿ÏàµÈ£®
£¨3£©ÊÇд³öPXÔÚ¿ÕÆøÖÐÍêȫȼÉÕ·´Ó¦µÄ»¯Ñ§·½³Ìʽ2C8H10+21O2$\frac{\underline{\;µãȼ\;}}{\;}$16CO2+10H2O£®

·ÖÎö £¨1£©²»ÐèҪͨ¹ý»¯Ñ§±ä»¯±íÏÖ³öÀ´µÄÐÔÖÊÊôÓÚÎïÖʵÄÎïÀíÐÔÖÊ£»
£¨2£©¸ù¾Ý»¯ºÏÎïÖÐÔªËØµÄÖÊÁ¿·ÖÊý=$\frac{Ïà¶ÔÔ­×ÓÖÊÁ¿¡ÁÔ­×Ó¸öÊý}{Ïà¶Ô·Ö×ÓÖÊÁ¿}$¡Á100%£¬½øÐзÖÎö½â´ð£»£®
£¨3£©¸ù¾Ý·´Ó¦Êéд»¯Ñ§·½³Ìʽ£¬Òª×¢Òâ¹æ·¶ÐÔ£®

½â´ð ½â£º£¨1£©PXµÄÑÕÉ«¡¢×´Ì¬¡¢È۵㡢·Ðµã¡¢Ãܶȡ¢ÆøÎ¶¡¢»Ó·¢ÐÔµÈÐÔÖʲ»ÐèҪͨ¹ý»¯Ñ§±ä»¯±íÏÖ³öÀ´£¬ÊôÓÚÎïÀíÐÔÖÊ£®
¹ÊÌ¢Ù¢Ú¢Û¢Ý£»
£¨2£©PXÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊýΪ£º$\frac{12¡Á8}{106}$¡Á100%¡Ö90.6%
¼×ÍéÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊýΪ£º$\frac{12}{12+1¡Á4}$¡Á100%=75%£»
Éè21.2gµÄPXÓëxg¼×Í麬̼Á¿ÏàµÈ£¬
21.2g¡Á90.6%=75%x
x¡Ö25.6g
¹ÊÌ90.6%£»25.6g£»
£¨3£©PXÔÚ¿ÕÆøÖÐÍêȫȼÉÕÄܹ»Éú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2C8H10+21O2$\frac{\underline{\;µãȼ\;}}{\;}$16CO2+10H2O£®
 ¹ÊÌ2C8H10+21O2$\frac{\underline{\;µãȼ\;}}{\;}$16CO2+10H2O£®

µãÆÀ ±¾ÌâÄѶȲ»´ó£¬¿¼²éͬѧÃǽáºÏÐÂÐÅÏ¢¡¢Áé»îÔËÓû¯Ñ§Ê½µÄÓйؼÆËã½øÐзÖÎöÎÊÌâ¡¢½â¾öÎÊÌâµÄÄÜÁ¦£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø