ÌâÄ¿ÄÚÈÝ

Çë¸ù¾ÝÏÂÁÐ×°Ö㬻شðÎÊÌ⣺

¢Åд³ö±êºÅ¢Ù¢ÚµÄÒÇÆ÷Ãû³Æ£º¢Ù¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¬¢Ú¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£
¢ÆÊµÑéÊÒÖÆÈ¡H2£¬¿ÉÑ¡ÓÃ×°Öá¡¡¡¡¡¡¡¡¡ £¨ÌîдװÖÃÐòºÅ£©ÄÜÊÕ¼¯µ½½Ï´¿¾»µÄH2¡£
¢ÇÅжÏCO2ÒÑÊÕ¼¯ÂúµÄ·½·¨ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£
¢ÈÓøßÃÌËá¼ØÖÆÈ¡O2£¬×°ÖÃA»¹Ðè×öµÄÒ»µã¸Ä¶¯ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£
¢É¶ÔÓÃÂÈËá¼ØºÍ¶þÑõ»¯Ã̵ĻìºÏÎïÖÆÈ¡O2ºóµÄ¹ÌÌå²ÐÔü£¨¼Ù¶¨ÒÑÍêÈ«·´Ó¦£©£¬Í¨¹ýÒÔÏÂËIJ½ÊµÑé²Ù×÷¿É»ØÊÕ¶þÑõ»¯ÃÌ¡£ÕýÈ·²Ù×÷µÄÏȺó˳ÐòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¨ÌîдѡÏîÐòºÅ£©¡£ a£®ºæ¸É¡¡¡¡¡¡¡¡ b£®Èܽ⡡¡¡¡¡¡¡¡¡¡¡ c£®¹ýÂË¡¡¡¡¡¡¡¡¡¡ d£®Ï´µÓ
¢Ê°Ñ¢ÉÖÐÂËÒºÕô·¢½á¾§¿ÉµÃµ½ÂÈ»¯¼Ø¾§Ì壬ÔÚÕô·¢²Ù×÷Öв£Á§°ôµÄ×÷ÓÃÊÇ¡¡¡¡¡¡¡¡¡¡¡¡

¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡¡ ¡£

¢ËÓÃ×°ÖÃFÖÆÈ¡ÆøÌ壬ÔÚ·´Ó¦¹ý³ÌÖУ¬Óõ¯»É¼Ð¼Ðסµ¼Æø¹ÜÉϵÄÏðÆ¤¹Ü£¬¹ýÒ»»á¶ù·´Ó¦¾Í»áÍ£Ö¹¡£ÆäÔ­ÒòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

£¨1£©³¤¾±Â©¶·£¬Ë®²Û£¨2£©B£¬D£¨3£©½«È¼ÉÕľÌõÉ쵽ƿ¿Ú£¬Ï¨Ãð£¬ËµÃ÷ÒÑÊÕ¼¯Âú

   £¨4£©ÊԹܿڷÅÒ»ÍÅÃÞ»¨£¨5£©bcda£¨6£©½Á°è£¬·ÀÖ¹ÒºÌå¾Ö²¿¹ýÈȷɽ¦³öÀ´

   £¨7£©Éú³ÉµÄÆøÌ彫·´Ó¦ÒºÌåѹ»Øµ½Â©¶·£¬Ê¹ÒºÌå¡¢¹ÌÌå²»ÔÙ½Ó´¥£¬·´Ó¦Í£Ö¹

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Çë¸ù¾ÝÏÂÁÐ×°Ö㬻شðÎÊÌ⣺

£¨1£©Ð´³ö±êºÅ¢Ù¢ÚµÄÒÇÆ÷Ãû³Æ£º¢Ù
³¤¾±Â©¶·
³¤¾±Â©¶·
£¬¢Ú
Ë®²Û
Ë®²Û
£®
£¨2£©ÊµÑéÊÒÖÆÈ¡H2£¬¿ÉÑ¡ÓÃ×°ÖÃ
BD
BD
£¨ÌîдװÖÃÐòºÅ£©ÄÜÊÕ¼¯µ½½Ï´¿¾»µÄH2£®
£¨3£©ÅжÏCO2ÒÑÊÕ¼¯ÂúµÄ·½·¨ÊÇ
½«È¼×ŵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬ÈôľÌõ»ðÑæÏ¨Ãð£¬ËµÃ÷¶þÑõ»¯Ì¼ÒÑÊÕ¼¯Âú
½«È¼×ŵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬ÈôľÌõ»ðÑæÏ¨Ãð£¬ËµÃ÷¶þÑõ»¯Ì¼ÒÑÊÕ¼¯Âú
£®
£¨4£©ÓøßÃÌËá¼ØÖÆÈ¡O2£¬×°ÖÃA»¹Ðè×öµÄÒ»µã¸Ä¶¯ÊÇ
ÔÚÊԹܿڷÅÒ»ÍÅÃÞ»¨
ÔÚÊԹܿڷÅÒ»ÍÅÃÞ»¨
£®
£¨5£©¶ÔÓÃÂÈËá¼ØºÍ¶þÑõ»¯Ã̵ĻìºÏÎïÖÆÈ¡O2ºóµÄ¹ÌÌå²ÐÔü£¨¼Ù¶¨ÒÑÍêÈ«·´Ó¦£©£¬Í¨¹ýÒÔÏÂËIJ½ÊµÑé²Ù×÷¿É»ØÊÕ¶þÑõ»¯ÃÌ£®ÕýÈ·²Ù×÷µÄÏȺó˳ÐòÊÇ
bcda
bcda
£¨ÌîдѡÏîÐòºÅ£©£®a£®ºæ¸É   b£®Èܽ⠠  c£®¹ýÂË    d£®Ï´µÓ
£¨6£©°Ñ£¨5£©ÖÐÂËÒºÕô·¢½á¾§¿ÉµÃµ½ÂÈ»¯¼Ø¾§Ì壬ÔÚÕô·¢²Ù×÷Öв£Á§°ôµÄ×÷ÓÃÊÇ
½Á¶¯£¬·ÀÖ¹¾Ö²¿Î¶ȹý¸ß¶øÔì³ÉÒºµÎ·É½¦£¨»òʹÊÜÈȾùÔÈ£©
½Á¶¯£¬·ÀÖ¹¾Ö²¿Î¶ȹý¸ß¶øÔì³ÉÒºµÎ·É½¦£¨»òʹÊÜÈȾùÔÈ£©
£®
£¨7£©ÓÃ×°ÖÃFÖÆÈ¡ÆøÌ壬ÔÚ·´Ó¦¹ý³ÌÖУ¬Óõ¯»É¼Ð¼Ðסµ¼Æø¹ÜÉϵÄÏðÆ¤¹Ü£¬¹ýÒ»»á¶ù·´Ó¦¾Í»áÍ£Ö¹£®ÆäÔ­ÒòÊÇ
·´Ó¦²úÉúµÄÆøÌå°ÑÒºÌåѹµ½UÐιÜ×ó¶Ë£¬Ê¹ÒºÌåÓë¸ô°åÉϵĹÌÌå·ÖÀ룬ֹͣ·´Ó¦
·´Ó¦²úÉúµÄÆøÌå°ÑÒºÌåѹµ½UÐιÜ×ó¶Ë£¬Ê¹ÒºÌåÓë¸ô°åÉϵĹÌÌå·ÖÀ룬ֹͣ·´Ó¦
£®
»¯Ñ§ÊµÑéÊÇѧϰ»¯Ñ§µÄ»ù´¡£¬Çë¸ù¾ÝÏÂÁÐ×°ÖÃͼ»Ø´ðÎÊÌ⣮

£¨1£©Ð´³öÒÇÆ÷a¡¢bµÄÃû³Æa
³¤¾±Â©¶·
³¤¾±Â©¶·
£»b
×¶ÐÎÆ¿
×¶ÐÎÆ¿
£®
£¨2£©Ð´³öAͼÖвúÉúÆøÌåµÄ»¯Ñ§·½³Ìʽ
CaCO3+2HCl=CaCl2+CO2¡ü+H2O
CaCO3+2HCl=CaCl2+CO2¡ü+H2O
£®
£¨3£©BͼÖУ¬°Ñ¶þÑõ»¯Ì¼ÆøÌåÂýÂýµ¹Èë·ÅÓÐȼ×ŵÄÀ¯ÖòµÄÉÕ±­ÖУ¬Ï²ãÀ¯ÖòÏÈÃð£¬ËµÃ÷¶þÑõ»¯Ì¼¾ßÓÐ
²»¿Éȼ
²»¿Éȼ
¡¢
²»Ö§³ÖȼÉÕ
²»Ö§³ÖȼÉÕ
ºÍ
ÃÜ¶È±È¿ÕÆø´ó
ÃÜ¶È±È¿ÕÆø´ó
ÐÔÖÊ£®ÕâÒ»ÐÔÖÊÔÚʵ¼ÊÉú»îÖеÄÓ¦ÓÃΪ
Ãð»ð
Ãð»ð
£®
£¨4£©CͼÖÐÂÝÐý×´ÌúË¿µÄÄ©¶Ëϵһ¸ù»ð²ñµÄ×÷ÓÃÊÇ
ÒýȼÌúË¿
ÒýȼÌúË¿
£®
£¨5£©Ð¡Ã÷°´CͼʵÑéʱ£¬¼¯ÆøÆ¿Õ¨ÁÑÁË£¬Æä¿ÉÄܵÄÔ­ÒòÊÇ
ȼ×ŵÄÌúË¿Åöµ½¼¯ÆøÆ¿±Ú
ȼ×ŵÄÌúË¿Åöµ½¼¯ÆøÆ¿±Ú
£®
£¨6£©Ð¡ö©¶ÔÌúË¿ÔÚÑõÆøÖÐȼÉÕΪʲô»á»ðÐÇËÄÉä½øÐÐ̽¾¿£®Ï±íÊÇËû½«´¿Ã¾ÌõºÍ²»Í¬º¬Ì¼Á¿µÄÌúË¿£¨Ã¾ÌõºÍÌú˿ֱ¾¶¾ùΪ0.4mm£©·ÅÈëÑõÆøÖÐȼÉÕʱµÄʵÑéÏÖÏóµÄ¼Ç¼£®ÇëÄãÌî±í²¢·ÖÎö»Ø´ð£®
ÎïÖÊ Ã¾Ìõ º¬Ì¼0.05%µÄÌúË¿ º¬Ì¼0.2%µÄÌúË¿ º¬Ì¼0.6%µÄÌúË¿
ÏÖÏó ¾çÁÒȼÉÕ£¬·¢³öÒ«
Ñ۰׹⣬ÎÞ»ðÐÇ
¾çÁÒȼÉÕ
¼«ÉÙ»ðÐÇ
¾çÁÒȼÉÕ
ÉÙÁ¿»ðÐÇ
¾çÁÒȼÉÕ£¬»ðÐÇËÄÉä
¾çÁÒȼÉÕ£¬»ðÐÇËÄÉä
ÄãÈÏΪ²úÉú»ðÐǵÄÔ­ÒòÊÇ£º
ÌúË¿Öк¬ÓеÄ̼ÒýÆðµÄ
ÌúË¿Öк¬ÓеÄ̼ÒýÆðµÄ
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø