ÌâÄ¿ÄÚÈÝ

ͬѧÃÇ´ÓɽÉϲɼ¯µ½Ò»ÖÖʯ»Òʯ£¬ËûÃÇÈ¡80¿Ë¸ÃÑùÆ·½øÐÐìÑÉÕʵÑé(Ëùº¬ÔÓÖÊ

ÔÚìÑÉÕ¹ý³ÌÖв»·¢Éú±ä»¯)£¬²âµÃ·´Ó¦ºó¹ÌÌåµÄÖÊÁ¿(m)Ó뷴Ӧʱ¼ä(t)µÄ¹ØÏµÈçÏÂ±í£º

·´Ó¦Ê±¼äts

t0

t1

t2

t3

t4

t5

t6

·´Ó¦ºó¹ÌÌåµÄÖÊÁ¿mg

80

75

70

66

62

58

58

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)µ±Ê¯»ÒʯÍêÈ«·´Ó¦ºó£¬Éú³ÉCO2µÄÖÊÁ¿Îª             g¡£

(2)Çó¸Ãʯ»ÒʯÖÐCaCO3µÄÖÊÁ¿·ÖÊý£¬Ð´³ö¼ÆËã¹ý³Ì¡£

(1)22g(2·Ö)

    (2)½â£ºÉèÑùÆ·Öк¬CaCO3µÄÖÊÁ¿Îªx

      

 CaCO3         CaO  + CO2 ¡ü                            (1·Ö)

          100                   44

           x                    22g                             (1·Ö)

 

=      x = =50g                     (2·Ö)

         ʯ»ÒʯÖÐCaCO3µÄÖÊÁ¿·ÖÊý=(50g¡Â80g)¡Á100£¥=62.5£¥       (1·Ö)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø