ÌâÄ¿ÄÚÈÝ

3£®Ä³ÐËȤС×éµÄͬѧΪÁ˲ⶨ̼ËáÄÆÑùÆ·£¨Ö»º¬ÓÐÂÈ»¯ÄÆ£¬²»º¬ÆäËüÔÓÖÊ£©ÖÐ̼ËáÄÆµÄº¬Á¿£¬È¡¸Ã»ìºÏÎïÑùÆ·ÓëÊÊÁ¿Ï¡ÑÎËáÇ¡ºÃÍêÈ«·´Ó¦£¬ÓйØÊµÑéÊý¾Ý¼û¸½±í£®
¸½±í£ºÊµÑéÊý¾Ý
 ·´Ó¦Ç°  ·´Ó¦ºó
ʵÑéÊý¾ÝÉÕ±­µÄÖÊÁ¿/gÏ¡ÑÎËáµÄÖÊÁ¿/g»ìºÏÎïÑùÆ·µÄÖÊÁ¿/gÉÕ±­ºÍÆäÖлìºÏÎïµÄÖÊÁ¿/g
40.6123.412171.6
£¨1£©·´Ó¦Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª4.4g£»
£¨2£©·´Ó¦ºóËùµÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýÊǶàÉÙ£¿£¨ÒªÓÐÏêϸµÄ¼ÆËã¹ý³Ì£©

·ÖÎö ¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ¿ÉÖª£¬¹ý³ÌÖÐÖÊÁ¿µÄ¼õÉÙÊÇÒòΪÉú³ÉÁ˶þÑõ»¯Ì¼£¬ËùÒÔ¿ÉÒÔÇóËã¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬¸ù¾Ý¶þÑõ»¯Ì¼µÄÖÊÁ¿ºÍ¶ÔÓ¦µÄ»¯Ñ§·½³ÌʽÇóËã̼ËáÄÆºÍÉú³ÉµÄÂÈ»¯ÄƵÄÖÊÁ¿£¬½ø¶øÇóËã¶ÔÓ¦ÈÜÒºÖÐÂÈ»¯ÄƵÄÖÊÁ¿·ÖÊý

½â´ð ½â£º¸ù¾ÝÖÊÁ¿Êغ㶨Âɿɵã¬Éú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª40.6g+123.4g+12g-171.6g=4.4g
Éè²Î¼Ó·´Ó¦µÄ̼ËáÄÆµÄÖÊÁ¿Îªx£¬Éú³ÉµÄÂÈ»¯ÄƵÄÖÊÁ¿Îªy
Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü
106                     117             44
x                            y             4.4g
$\frac{106}{x}$=$\frac{117}{y}$=$\frac{44}{4.4g}$
x=10.6g
y=11.7g
·´Ó¦ºóËùµÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ$\frac{12g-10.6g+11.7g}{171.6g-40.6g}$¡Á100%=10%
´ð£º£¨1£©·´Ó¦Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª 4.4g£»
£¨2£©·´Ó¦ºóËùµÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýÊÇ10%£®

µãÆÀ ¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆËãʱ£¬µÚÒ»ÒªÕýÈ·Êéд»¯Ñ§·½³Ìʽ£¬µÚ¶þҪʹÓÃÕýÈ·µÄÊý¾Ý£¬µÚÈý¼ÆËã¹ý³ÌÒªÍêÕû£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø