ÌâÄ¿ÄÚÈÝ

2£®ÓÃÀ´²â¶¨¿ÕÆø³É·Öº¬Á¿µÄ·½·¨Óкܶ࣬ÈçͼËùʾµÄʹÓÃ×ãÁ¿ºìÁ×ÔÚ¿ÕÆøÖÐȼÉյķ½·¨²â¶¨¿ÕÆøÖÐÑõÆøµÄº¬Á¿£®
£¨1£©Ð´³ö¸Ã¹ý³Ì·¢ÉúµÄ»¯Ñ§·´Ó¦Ê½£º4P+5O2$\frac{\underline{\;µãȼ\;}}{\;}$2P2O5£®
£¨2£©¼¯ÆøÆ¿ÈÝ»ýΪ125mL£¨ÒÑÓÐË®µÄÌå»ýºöÂÔ²»¼Æ£©£¬ºìÁ×ȼÉÕǰ£¬×¢ÉäÆ÷¿Ì¶ÈÍ£ÔÚ75mL´¦£¨×¢ÉäÆ÷×î´ó¿Ì¶ÈΪ100mL£¬¼ÙÉè×¢ÉäÆ÷ÈÝ»ý×ã¹»£©£®µãȼºìÁ×£¬´ýÆäϨÃðÇÒ×°ÖÃÀäÈ´µ½ÊÒκó£¬ÀíÂÛÉÏ»îÈûӦͣÔڿ̶ÈÔ¼35mL´¦£¬Êµ¼ÊÍ£ÔÚ37mL´¦£¬Ôò²âµÃµÄ¿ÕÆøÖÐÑõÆøº¬Á¿±ÈÀíÂÛֵƫС£¨Ìî¡°Æ«´ó¡±»ò¡°Æ«Ð¡¡±£©
£¨3£©¼ÆËãÕû¸ö×°ÖÃÖеªÆøµÄÖÊÁ¿Ó¦Îª¶àÉÙ¿Ë£¿£¨µªÆøµÄÃܶÈΪ1.25g/L£©

·ÖÎö ºìÁ×ȼÉÕÉú³ÉÎåÑõ»¯¶þÁ×£»
ÑõÆøÔ¼Õ¼¿ÕÆø×ÜÌå»ýµÄÎå·ÖÖ®Ò»£»
¸ù¾ÝµªÆøµÄÌå»ý¡¢ÃܶȿÉÒÔ¼ÆËãµªÆøµÄÖÊÁ¿£®

½â´ð ½â£º£¨1£©ºìÁ×ȼÉյĻ¯Ñ§·½³ÌʽΪ£º4P+5O2$\frac{\underline{\;µãȼ\;}}{\;}$2P2O5£®
¹ÊÌ4P+5O2$\frac{\underline{\;µãȼ\;}}{\;}$2P2O5£®
£¨2£©ÀíÂÛÉϺìÁ×ÏûºÄÑõÆøµÄÌå»ýΪ£º£¨125mL+75mL£©¡Á$\frac{1}{5}$=40mL£¬
ÀíÂÛÉÏ»îÈûӦͣÔڿ̶ÈÔ¼£¨75mL-40mL=35mL£©´¦£»
ʵ¼ÊÍ£ÔÚ37mL´¦£¬ËµÃ÷ÏûºÄµÄÑõÆøÌå»ýƫС£¬Ôòµ¼Ö²âµÃµÄ¿ÕÆøÖÐÑõÆøº¬Á¿±ÈÀíÂÛֵƫС£®
¹ÊÌ35£»Æ«Ð¡£®
£¨3£©Õû¸ö×°ÖÃÖеªÆøµÄÖÊÁ¿Ó¦Îª£º1.25g/L¡Á£¨0.125L+0.075L£©=0.25g£¬
´ð£ºÕû¸ö×°ÖÃÖеªÆøµÄÖÊÁ¿Ó¦Îª0.25g£®

µãÆÀ ºÏÀíÉè¼ÆÊµÑ飬¿ÆÑ§µØ½øÐÐʵÑé¡¢·ÖÎöʵÑ飬ÊǵóöÕýȷʵÑé½áÂÛµÄǰÌᣬÒò´ËҪѧ»áÉè¼ÆÊµÑé¡¢½øÐÐʵÑé¡¢·ÖÎöʵÑ飬ΪѧºÃ»¯Ñ§ÖªÊ¶µì¶¨»ù´¡£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø