ÌâÄ¿ÄÚÈÝ
10£®ÔÚ¡°2H3PO4¡±µÄ»¯Ñ§·ûºÅÖУ¬ÓС°1¡¢2¡¢3¡¢4¡±ËĸöÊý×Ö£¬ÏÂÁжԷûºÅÖеÄÊý×ÖÃèÊö²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©| A£® | ÔÚ¡°2H3PO4¡±»¯Ñ§·ûºÅÖе쬡°1¡±±íʾһ¸öÁ×ÔªËØ | |
| B£® | ÔÚ¡°2H3PO4¡±»¯Ñ§·ûºÅÖе쬡°2¡±±íʾÁ½¸öH3PO4·Ö×Ó | |
| C£® | ÔÚ¡°2H3PO4¡±»¯Ñ§·ûºÅÖе쬡°3¡±±íʾÿ¸öH3PO4·Ö×Óº¬ÓÐÈý¸öÇâÔ×Ó | |
| D£® | ÔÚ¡°2H3PO4¡±»¯Ñ§·ûºÅÖе쬡°4¡±±íʾÿ¸öH3PO4·Ö×Óº¬ÓÐËĸöÑõÔ×Ó |
·ÖÎö A¡¢±êÔÚ»¯Ñ§Ê½ÖÐÔªËØÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô×ÓµÄÊýÄ¿£®
B¡¢±êÔÚ·Ö×Ó·ûºÅÇ°ÃæµÄÊý×Ö±íʾ·Ö×ӵĸöÊý£®
C¡¢±êÔÚ»¯Ñ§Ê½ÖÐÔªËØÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô×ÓµÄÊýÄ¿£®
D¡¢±êÔÚ»¯Ñ§Ê½ÖÐÔªËØÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô×ÓµÄÊýÄ¿£®
½â´ð ½â£ºA¡¢±êÔÚ»¯Ñ§Ê½ÖÐÔªËØÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô×ÓµÄÊýÄ¿£¬ÔÚ¡°2H3PO4¡±Öеġ°1¡±±íʾ1¸öÁ×Ëá·Ö×ÓÖк¬ÓÐ1¸öÁ×Ô×Ó£¬ÔªËØÖ»½²ÖÖÀà¡¢²»½²¸öÊý£¬¹ÊÑ¡Ïî˵·¨´íÎó£®
B¡¢±êÔÚ·Ö×Ó·ûºÅÇ°ÃæµÄÊý×Ö±íʾ·Ö×ӵĸöÊý£¬¡°2H3PO4¡±Öеġ°2¡±±íʾÁ×Ëá·Ö×ӵĸöÊýΪ2£¬¹ÊÑ¡Ïî˵·¨ÕýÈ·£®
C¡¢±êÔÚ»¯Ñ§Ê½ÖÐÔªËØÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô×ÓµÄÊýÄ¿£¬ÔÚ¡°2H3PO4¡±Öеġ°3¡±±íʾ1¸öÁ×Ëá·Ö×ÓÖк¬ÓÐ3¸öÇâÔ×Ó£¬¹ÊÑ¡Ïî˵·¨ÕýÈ·£®
D¡¢±êÔÚ»¯Ñ§Ê½ÖÐÔªËØÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô×ÓµÄÊýÄ¿£¬ÔÚ¡°2H3PO4¡±Öеġ°4¡±±íʾ1¸öÁ×Ëá·Ö×ÓÖк¬ÓÐ4¸öÑõÔ×Ó£¬¹ÊÑ¡Ïî˵·¨ÕýÈ·£®
¹ÊÑ¡£ºA£®
µãÆÀ ±¾ÌâÄѶȲ»´ó£¬Ö÷Òª¿¼²éÁËÔªËØ·ûºÅ²»Í¬Î»ÖõÄÊý×Ö±íʾµÄÒâÒ壬կÎÕ±êÔÚÔªËØ·ûºÅ²»Í¬Î»ÖõÄÊý×ÖËù±íʾµÄÒâÒåÊÇÕýÈ·½â´ð´ËÀàÌâµÄ¹Ø¼üËùÔÚ£®
| A£® | ËùÓл¯Ñ§·´Ó¦¶¼·ÅÈÈ | B£® | ÔÚ¸ÖÌú±íÃæÍ¿ÓÍ¿ÉÒÔ·ÀÖ¹ÉúÐâ | ||
| C£® | Ë®Òø¡¢¸É±ù¡¢Ê¯ÓͶ¼ÊôÓÚ»ìºÏÎï | D£® | Óе¥ÖÊÉú³ÉµÄ·´Ó¦Ò»¶¨ÎªÖû»·´Ó¦ |
| A£® | ¸ÃʵÑéÐèÒªµÄÒÇÆ÷Ö»Óоƾ«µÆ¡¢²£Á§°ô¡¢ÉÕ±¡¢Á¿Í²¡¢Â©¶·¡¢Õô·¢Ãó | |
| B£® | ¸ÃʵÑéµÄÖ÷ҪʵÑé¹ý³ÌÊdzÆÁ¿¡¢¹ýÂË¡¢Õô·¢¡¢¼ÆËã²úÂÊ | |
| C£® | Õô·¢ÂËҺʱ£¬Õô·¢ÃóÖеÄˮȫ²¿Õô¸Éºó²ÅÄÜÍ£Ö¹¼ÓÈÈ | |
| D£® | ÔÚ½øÐйýÂ˲Ù×÷ʱ£¬²£Á§°ôµÄ×÷ÓÃÊÇÒýÁ÷ÒºÌå |
| ÎïÖÊ | ¼× | ÒÒ | ±û | ¶¡ |
| ·´Ó¦Ç°µÄÖÊÁ¿/g | 2 | 30 | 20 | 10 |
| ·´Ó¦ºóµÄÖÊÁ¿/g | m | 39 | 5 | 16 |
| A£® | ¼×ÊǸ÷´Ó¦µÄ´ß»¯¼Á | B£® | ±û¿ÉÄÜÊǵ¥ÖÊ | ||
| C£® | ÒÒ¡¢±ûÔÚ·´Ó¦ÖеÄÖÊÁ¿±ÈΪ3£º5 | D£® | ¸Ã·´Ó¦ÊÇ»¯ºÏ·´Ó¦ |
| A£® | ¸Ã»¯Ñ§·´Ó¦·¢ÉúµÄÊǷֽⷴӦ | B£® | ¸Ã»¯Ñ§·´Ó¦·¢ÉúµÄÊÇ»¯ºÏ·´Ó¦ | ||
| C£® | ÒÒ¡¢±ûʱ·´Ó¦Î¼×ÊÇÉú³ÉÎï | D£® | ¼×µÄÖÊÁ¿µÈÓÚÒÒ¡¢±ûÖÊÁ¿Ö®ºÍ |
| A£® | ²â¶¨ÈÜÒºËá¼î¶È | B£® | ÊÕ¼¯¶þÑõ»¯Ì¼ | C£® | Çãµ¹ÒºÌå | D£® | ϨÃð¾Æ¾«µÆ |
| A | B | C |
| H2 | H2O | Ca£¨OH£©2 |
| C | CO2 | Ca CO3 |
£¨2£©Ë׳ÆÊìʯ»ÒµÄÊÇCa£¨OH£©2£®
£¨3£©½«6ÖÖÎïÖÊ·ÖΪA¡¢B¡¢CÈý×éµÄÒÀ¾ÝÊÇÔªËØÖÖÊýÏàͬ£®
£¨4£©ÔÚÉÏÊöÎïÖÊ¿ÉÒÔת»¯µÄ·´Ó¦ÖУ¬Äܹ»Ö¤Ã÷¡°Ë®¡±×÷Ϊѻ·ÎïÖʵĻ¯Ñ§·½³ÌʽÊÇCO2+Ca£¨OH£©2=CaCO3¡ý+H2O£»H2O+CaO$\frac{\underline{\;\;¡÷\;\;}}{\;}$Ca£¨OH£©2£®
| A£® | CH3COCH3 | B£® | CH3COOH | C£® | CH4 | D£® | C |