ÌâÄ¿ÄÚÈÝ

14£®»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©½ð¸ÕʯÓëʯī¶¼ÊÇÓÉÌ¼ÔªËØ×é³ÉµÄµ¥ÖÊ£¬µ«ËüÃǵÄÎïÀíÐÔÖÊÓкܴóµÄ²îÒ죬ÆäÔ­ÒòÊÇÔ­×ÓµÄÅÅÁз½Ê½²»Í¬£»
£¨2£©½«¼¸¿éºæ¿¾¹ýµÄľ̿ͶÈëµ½µÎÓÐÉÙÁ¿ºìīˮµÄË®ÖУ¬Õñµ´ºó¿É¹Û²ìµ½ºìīˮÍÊÉ«£»ÕâÊÇÒòΪľ̿¾ßÓÐÎü¸½ÄÜÁ¦£»
£¨3£©µ±½ñÊÀ½çÉÏ×îÖØÒªµÄÈý´ó»¯Ê¯È¼ÁÏÊÇú¡¢Ê¯ÓÍ¡¢ÌìÈ»Æø£»
£¨4£©ÔÚÒ»Çл¯Ñ§·´Ó¦À·´Ó¦Ç°ºóÔ­×ÓµÄÖÖÀàûÓиı䣬ԭ×ÓÊýĿҲûÓÐÔö¼õ£¬Ô­×ÓµÄÖÊÁ¿Ò²Ã»Óиı䣬ËùÒÔ»¯Ñ§·´Ó¦Ç°ºó¸÷ÎïÖʵÄÖÊÁ¿×ܺͱØÈ»ÏàµÈ£®

·ÖÎö £¨1£©¸ù¾Ý½ð¸ÕʯºÍʯīµÄ̼ԭ×ÓµÄÅÅÁз½Ê½½øÐзÖÎö£»
£¨2£©¸ù¾Ýºæ¿¾¹ýµÄľ̿¾ßÓÐÎü¸½×÷Ó÷ÖÎö£»
£¨3£©¸ù¾Ý»¯Ê¯È¼ÁϵÄÖÖÀà·ÖÎö£»
£¨4£©¸ù¾ÝÖÊÁ¿Êغ㶨Âɽâ´ð£®

½â´ð ½â£º£¨1£©½ð¸ÕʯÓëʯī¶¼ÊÇÓÉÌ¼ÔªËØ×é³ÉµÄµ¥ÖÊ£¬µ«ËüÃǵÄÎïÀíÐÔÖÊÓкܴóµÄ²îÒ죬ÆäÔ­ÒòÊÇ̼ԭ×ÓÅÅÁз½Ê½²»Í¬£»
£¨2£©½«¼¸¿éºæ¿¾¹ýµÄľ̿ͶÈëµ½µÎÓÐÉÙÁ¿ºìīˮµÄË®ÖУ¬ÒòΪľ̿¾ßÓÐÎü¸½ÄÜÁ¦£¬Õñµ´ºó¿É¹Û²ìµ½ºìīˮÑÕÉ«Öð½¥ÍËÈ¥£»
£¨3£©Ãº£¬Ê¯ÓÍ£¬ÌìÈ»ÆøÊǵ±½ñÊÀ½çÉÏ×îÖØÒªµÄÈý´ó»¯Ê¯È¼ÁÏ£»
£¨4£©ÔÚÒ»Çл¯Ñ§·´Ó¦À·´Ó¦Ç°ºóÔ­×ÓµÄÖÖÀàûÓиı䣬ԭ×ÓÊýĿҲûÓÐÔö¼õ£¬Ô­×ÓµÄÖÊÁ¿Ò²Ã»Óиı䣬ËùÒÔ»¯Ñ§·´Ó¦Ç°ºó¸÷ÎïÖʵÄÖÊÁ¿×ܺͱØÈ»ÏàµÈ£®
¹Ê´ð°¸Îª£º
£¨1£©Ì¼Ô­×ÓµÄÅÅÁз½Ê½²»Í¬£»
£¨2£©ºìīˮÍÊÉ«£»Îü¸½£»
£¨3£©Ãº¡¢Ê¯ÓÍ¡¢ÌìÈ»Æø£»
£¨4£©ÖÖÀࣻ ÊýÄ¿£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éÎïÖʵÄÐÔÖʲîÒìµÄÔ­ÒòºÍľ̿µÄÎü¸½ÄÜÁ¦£¬½â´ðʱҪ³ä·ÖÀí½â¸÷ÖÖÎïÖʵÄÐÔÖÊ£¬È»ºóÔÙ¸ù¾ÝÎïÖʵÄÐÔÖÊ·½Ãæ½øÐзÖÎö¡¢Åжϣ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
6£®ÏÂÁÐÈý¸öʵÑé¾ù¿ÉÖ¤Ã÷CO2ÄÜÓëNaOHÈÜÒº·´Ó¦£®
ʵÑé¢ñ£ºÓÃÊԹܼ¯ÂúCO2£¬Ñ¸ËÙ¼ÓÈëNaOHÈÜÒº¡¢Èû½ôÏðƤÈû£¬³ä·ÖÕñµ´£¬¾²Öã®
£¨1£©ÊµÑéºó´ò¿ªÏðƤÈûʱ£¬Ìýµ½ÏìÁÁµÄ¡°à£¡±Éù£¬ÆäÔ­ÒòÊÇʵÑéºóÊÔ¹ÜÖÐµÄÆøÑ¹±äС£¨Ìî¡°±ä´ó¡±»ò¡°±äС¡±£©£»
£¨2£©¶Ô¾²ÖúóµÄÈÜÒº½øÐÐÏÂÁвÙ×÷£¬ÓɶÔÓ¦µÄÏÖÏó¿ÉÍÆÖªCO2ÓëNaOHÈÜÒºÒ»¶¨·´Ó¦µÄÊÇc£¨ÌîÐòºÅ£©£®
a£®µÎ¼Ó·Ó̪£¬ÈÜÒº±äΪºìÉ«
b£®µÎ¼ÓÉÙÁ¿Ï¡ÑÎËᣬ²»²úÉúÆøÅÝ
c£®µÎ¼ÓÉÙÁ¿ÂÈ»¯±µÈÜÒº£¬²úÉú°×É«³Áµí
ʵÑé¢ò£ºÔÚ8.0g NaOH¹ÌÌåÖмÓÈëÊÊÁ¿95%µÄÒÒ´¼ÈÜÒº£¬ÅäÖÆ³É±¥ºÍNaOHµÄÒÒ´¼ÈÜÒº£¬Ïò¸ÃÈÜÒºÖÐͨÈëCO2£¬Ö±ÖÁ²úÉú°×É«³ÁµíNa2CO3£®
£¨3£©Ä³ÍÐÅÌÌìÆ½±ê³ßµÄ×î´ó¿Ì¶ÈΪ1g£¬Å䱸ÓÐ1g¡¢2g¡¢5gºÍ10gËÄÖÖíÀÂëÈô¸É¸ö£¬ÓøÃÌìÆ½³ÆÈ¡8.0gNaOH¹ÌÌåʱ£¬ËùÐèíÀÂë×ÜÊýΪ3¸ö£»
£¨4£©ÊµÑé¢òÀûÓõÄÔ­ÀíÊÇ£ºÈܼÁµÄÖÖÀàÓ°ÏìÎïÖʵÄÈܽâÐÔ£®
ʵÑé¢ó£ºÈçͼËùʾ£¬½«5mLÈÜÖÊÖÊÁ¿·ÖÊýΪ10%µÄNaOHÈÜÒº£¨¦Ñ¡Ö1.1g/mL£©»ºÂý¡¢È«²¿×¢ÉäÈëÆ¿ÖУ¬¹Û²ìµ½µÄ¾Æ¾«µ¹Á÷ÈëÆ¿ÖУ¬×îÖÕÆ¿ÖÐÊ£Óà5mLÆøÌ壮´ËʵÑéÌõ¼þÏ£¬1Ìå»ýˮԼ¿ÉÈÜ1Ìå»ýCO2£¬CO2²»ÈÜÓھƾ«£¬¦Ñ£¨CO2£©¡Ö2g/L£®

£¨5£©ÊµÑéʱ²»ÄÜ£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©ÓÃË®´úÌæÁ¿Í²Öеľƾ«£»
£¨6£©ÊµÑéʱ½«NaOHÈÜÒº»ºÂý×¢ÉäÈëÆ¿ÖеÄÔ­ÒòÊÇ·ÀÖ¹¶þÑõ»¯Ì¼ÆøÌå´Óµ¼¹ÜÒݳö£»
£¨7£©¸ù¾ÝÉÏÊöʵÑé¿ÉÍÆÖª£ºÓëNaOHÈÜÒº·´Ó¦µÄCO2ԼΪ75£¨È¡ÕûÊý£©mL£®
£¨8£©ÀíÂÛÉÏ£¬ÉÏÊö5mL NaOHÈÜÒºÓë×ãÁ¿CO2·´Ó¦¶¼×ª»¯ÎªNa2CO3ʱ£¬²Î¼Ó·´Ó¦µÄCO2µÄÌå»ýԼΪ¶àÉÙºÁÉý£¿£¨Ð´³ö¼ÆËã¹ý³Ì£¬½á¹ûÈ¡ÕûÊý£©
£¨9£©Êµ¼ÊÉÏ£¬ÉÏÊöNaOHÈÜÒºÎüÊÕµÄCO2Æ«ÉÙ£¬ÆäÔ­Òò¿ÉÄÜÊÇa¡¢b¡¢d£¨ÌîÐòºÅ£©£®
a£®CO2²»´¿
b£®×°ÖÃÂ©Æø
c£®NaOHÓëCO2»¯ºÏÉú³ÉÁËNaHCO3
d£®µ¹Á÷ÈëÆ¿Öеľƾ«¸ÉÈÅÁËNaOHÈÜÒº¶ÔCO2µÄÎüÊÕ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø