ÌâÄ¿ÄÚÈÝ

14£®Ä³Ð¡×éͬѧ̽¾¿¶þÑõ»¯Ì¼£¨CO2£©¡¢°±Æø£¨NH3£©·Ö±ðÓëË®·´Ó¦ºó²úÎïµÄËá¼îÐÔ£®ËûÃÇÊÕ¼¯ÁËÈô¸ÉÆ¿CO2ºÍNH3£®
¡¾È·¶¨±ê×¼¡¿

ÀÏʦָµ¼¸ÃС×éͬѧÓÃ×ÔÖÆµÄ×ÏɫʯÈïÊÔÖ½Íê³ÉÁËÈçÉÏͼËùʾʵÑ飬ȷ¶¨¼ìÑéËá¼îÐÔÎïÖÊ´æÔڵıê×¼£®È¡Èý¸ö½à¾»µÄ±íÃæÃ󣬷ֱð·ÅÉÏ×ÏɫʯÈïÊÔÖ½£¬ÏòÊÔÖ½ÉÏÒÀ´ÎµÎ¼ÓÏ¡ÑÎËá¡¢ÕôÁóË®¡¢ÇâÑõ»¯ÄÆ£¨¼î£©ÈÜÒº£¬¹Û²ìµ½ÈýÌõÊÔÖ½µÄÑÕÉ«ÒÀ´ÎΪºìÉ«¡¢×ÏÉ«ºÍÀ¶É«£®
¡¾ÊµÑé¹ý³Ì¡¿
£¨1£©Ì½¾¿CO2ÓëË®·´Ó¦²úÎïµÄËá¼îÐÔ£®¸ÃС×éͬѧÏòһƿCO2ÖмÓÈë30mLË®£¬³ä·ÖÕñµ´£®ÔÙȡһ¸ö½à¾»µÄ±íÃæÃ󣬷ÅÉÏÒ»Ìõ×ÏɫʯÈïÊÔÖ½£¬ÏòÊÔÖ½ÉÏµÎ¼ÓÆ¿ÖеÄÒºÌ壬¹Û²ìµ½×ÏɫʯÈïÊÔÖ½±ä³ÉºìÉ«£¬ÓÉ´Ë»ñµÃ½áÂÛ£ºÆ¿ÖÐÒºÌåÀﺬÓÐËáÐÔÎïÖÊ£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCO2+H2O¨TH2CO3£®
£¨2£©Ì½¾¿NH3ÓëË®·´Ó¦²úÎïµÄËá¼îÐÔ£®¸ÃС×éͬѧÓã¨1£©µÄ·½·¨¼ÌÐø½øÐÐNH3µÄʵÑ飬ËûÃÇ·ÖÎöÒºÌåÀﺬÓмîÐÔÎïÖÊ£¬¹Û²ìµ½µÄÏÖÏóÊÇ£¬·ÖÎöÒÀ¾ÝÊÇ×ÏɫʯÈïÊÔÖ½±äΪÀ¶É«£»¼îÐÔÈÜҺʹ×ÏɫʯÈïÊÔÖ½±ä³ÉÀ¶É«£®
¡¾ÊµÑ鷴˼¡¿
ÓÐͬѧÌá³ö£º½öÓÃÉÏÊöʵÑ黹²»×ãÒÔ˵Ã÷CO2»òNH3ÓëË®·¢ÉúÁË·´Ó¦£¬»¹Ðè²¹³äÒ»¸ö¶Ô±ÈʵÑ飬ÒÔNH3ΪÀý£¬¸Ã¶Ô±ÈʵÑéµÄ²Ù×÷Ϊ½«¸ÉÔï×ÏɫʯÈïÊÔÖ½·ÅÈëÁíһƿNH3ÆøÌåÖУ¬¹Û²ìµ½µÄÏÖÏóΪÊÔÖ½²»±äÉ«£®

·ÖÎö £¨1£©¸ù¾Ý×ÏɫʯÈïÊÔÒºÓöËá±äºìÉ«ºÍ»¯Ñ§·½³ÌʽµÄÊéд·½·¨À´Êéд£»
£¨2£©¸ù¾Ý×ÏɫʯÈïÊÔÒºÓö¼î±äÀ¶É«£»°±Æø²»ÏÔ¼îÐÔÀ´·ÖÎö½â´ð£»

½â´ð ½â£º×ÏɫʯÈïÊÔÒºÓöËá±äºì£¬ÏòÊÔÖ½ÉÏµÎ¼ÓÆ¿ÖеÄÒºÌ壬×ÏɫʯÈïÊÔÖ½±ä³ÉºìÉ«£¬ËµÃ÷Æ¿ÖÐÒºÌ庬ÓÐËáÐÔÎïÖÊ£»¶þÑõ»¯Ì¼ºÍË®·´Ó¦Ö»ÄÜÉú³É̼Ë᣻
¹Ê´ð°¸Îª£ºËá        CO2+H2O¨TH2CO3
£¨2£©×ÏɫʯÈïÊÔÖ½Óö¼îÐÔÈÜÒº±ä³ÉÀ¶É«£»²¹³äÒ»¸ö¶Ô±ÈʵÑé¹Û²ì°±ÆøÄܲ»ÄÜʹ¸ÉÔï×ÏɫʯÈïÊÔÒº±äÀ¶£¬¿ÉÒÔ˵Ã÷²»Êǰ±ÆøÊ¹Ê¯ÈïÊÔÖ½±äÀ¶É«£¬¶øÊǰ±ÆøÓëË®·´Ó¦Éú³ÉµÄ¼îʹʯÈïÊÔÖ½±äÀ¶É«£»
¹Ê´ð°¸Îª£º×ÏɫʯÈïÊÔÖ½±äΪÀ¶É«£¬¼îÐÔÈÜҺʹ×ÏɫʯÈïÊÔÖ½±ä³ÉÀ¶É«£»
½«¸ÉÔï×ÏɫʯÈïÊÔÖ½·ÅÈëÁíһƿNH3ÆøÌåÖУ»ÊÔÖ½²»±äÉ«

µãÆÀ ±¾Ì⿼²éÁËÎïÖÊÏÖÔÚµÄʵÑéÑéÖ¤·½·¨ºÍʵÑéÉè¼Æ¡¢ÅжϺͼìÑ飬ÌâÄ¿ÄѶÈÖеȣ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
2£®¼¸Î»Í¬Ñ§¸ù¾ÝÏÂÁи÷ʵÑé×°ÖÃͼ£¬Éè¼ÆºÍÌÖÂÛÁËÒÔÏÂÎÊÌ⣺

£¨1£©Áõ³¬Í¬Ñ§Ëµ£ºÑ¡ÔñAÓëE×éºÏ³É×°Öò¢ÔÚÊԹܿڼÓÒ»ÍÅÃÞ»¨¿ÉÖÆÈ¡²¢ÊÕ¼¯½Ï´¿¾»µÄÑõÆø£¬Æä·´Ó¦µÄ·ûºÅ±í´ïʽΪ2KMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü£®
£¨2£©ÀîÔÃͬѧ˵£ºÓùýÑõ»¯ÇâºÍ¶þÑõ»¯ÃÌ»ìºÏÒ²¿ÉÒÔÖÆÈ¡ÑõÆø£¬·¢Éú×°ÖÃӦѡÔñB£¬·´Ó¦µÄ·ûºÅ±í´ïʽΪ2H2O2$\frac{\underline{\;MnO_2\;}}{\;}$2H2O+O2¡ü£®
£¨3£©Îº³Éͬѧ˵£º¡°D×°ÖÃ×°ÂúË®ºó¿ÉÒÔÊÕ¼¯²¢´¢´æÑõÆø£¬ÐèÒªÑõÆøÊ±¿ÉÓÃË®½«×°ÖÃÖеÄÑõÆøÅųö£¬Ë®Ó¦´Ó£¨Ìîa»òb£©a¶ËͨÈ룮¡±
£¨4£©³É·Éͬѧ˵£º¡°ÎÒ¿´µ½¿ÎÍâ×ÊÁÏÉϽéÉÜ£¬ÊµÑéÊÒ¿ÉÓÿé×´Áò»¯ÑÇÌú£¨FeS£©ÓëÏ¡ÁòËá·´Ó¦ÖÆÈ¡Áò»¯ÇâÆøÌ壨H2S£©£®Áò»¯ÇâÆøÌåµÄÃÜ¶È±È¿ÕÆø´ó£¬ÄÜÈÜÓÚË®ÐγÉÇâÁòËᣮ¸ù¾ÝÒÔÉÏ֪ʶ£¬ÎÒÏÖÔÚÃ÷°×ÁË£ºÊµÑéÊÒÖÆÈ¡Áò»¯ÇâÆøÌåӦѡÓõķ¢Éú×°ÖÃÊÇB£¬ÊÕ¼¯×°ÖÃÊÇG£¬H£®
£¨5£©Ð¡Ãôͬѧͨ¹ý²éÔÄ×ÊÁϵÃÖª£º°±ÆøÔÚͨ³£×´¿öÏÂÊÇÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøÎ¶µÄÆøÌ壬ÃÜ¶È±È¿ÕÆøÐ¡£¬¼«Ò×ÈÜÓÚË®£¬ÆäË®ÈÜҺΪ°±Ë®£®ÊµÑéÊÒÖÆÈ¡°±ÆøÈôÓÃÈçͼÖÐH×°ÖÃÊÕ¼¯°±ÆøÊ±£¬ÆøÌåÓ¦´Ób£¨Ìîa»òb£©µ¼Æø¹Ü½øÈëÆ¿ÖУ¬Ô­ÒòÊǰ±ÆøÃÜ¶È±È¿ÕÆøÐ¡£®Èô½«¼¯Âú°±ÆøµÄÊԹܵ¹ÖÃÓÚÈçͼIËùʾµÄË®²ÛÖУ¬²¢¹Ì¶¨ÊԹܣ¬Ò»¶Îʱ¼äºó£¬¹Û²ìµ½µÄʵÑéÏÖÏóÊÇÊÔ¹ÜÄÚÒºÃæÉÏÉý£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø