ÌâÄ¿ÄÚÈÝ

ºÏ³É°±¹¤ÒµÖУ¬³£ÓÃ̼Ëá¼ØÈÜÒºÎüÊÕ²úÉúµÄ¶þÑõ»¯Ì¼µÃµ½Ì¼ËáÇâ¼Ø£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºK2CO3+CO2+H2O=2KHCO3.ÏÖÏò̼Ëá¼ØÈÜÒºÖÐͨÈë¶þÑõ»¯Ì¼£¬Ç¡ºÃÍêÈ«·´Ó¦£¬µÃµ½ÈÜÖʵÄÖÊÁ¿·ÖÊýΪ10%µÄÈÜÒº50g£¬ÊÔ¼ÆË㣺

£¨1£©Ì¼Ëá¼ØÖмØÔªËØ¡¢Ì¼ÔªËØ¡¢ÑõÔªËØµÄÖÊÁ¿±ÈΪ_____________¡£

£¨2£©Èô°Ñ¸Ã50gÈÜÒº£¬Ï¡ÊÍΪÖÊÁ¿·ÖÊýΪ4%µÄÈÜÒº£¬ÐèÒª¼ÓÈëË®µÄÖÊÁ¿¡£

£¨3£©Ô­Ì¼Ëá¼ØÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£¨¼ÆËã½á¹û¾«È·µ½0.1%£©¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø