ÌâÄ¿ÄÚÈÝ
ʵÑéÓë̽¾¿ÊÇ»¯Ñ§Ñ§Ï°µÄÖØÒª·½·¨ºÍÄÚÈÝ¡£
£¨1£©Ð¡ÕÅͬѧ½øÐеÄʵÑ鿼²éÊÇ¡°ÓÃÏ¡ÑÎËá¼ø±ðÇâÑõ»¯ÄÆ£¨NaOH£©ÈÜÒººÍ̼ËáÄÆ£¨Na2CO3£©ÈÜÒº£¬²¢²â¶¨Ì¼ËáÄÆÈÜÒºµÄpH¡±¡£
¢ÙСÕÅͬѧµÄʵÑé¼Ç¼ÈçÏÂ±í£¬Çë²¹³äÍêÕû£º
| ²Ù×÷²½Öè | ÏÖÏó¼Ç¼ | ·´Ó¦µÄ»¯Ñ§·½³Ìʽ |
| È¡Á½Ö§ÊԹܣ¬·Ö±ðÍùÊÔ¹ÜÖмÓÈë2mLÑùÆ·1¡¢2£¬ÔÙÍùÆäÖеÎÈëÑÎËá | ÑùÆ·1£ºÎÞÃ÷ÏÔÏÖÏó | ___________________ |
| ÑùÆ·2£º
| ___________________ |
¢ÚÓÃpHÊÔÖ½²â¶¨Ì¼ËáÄÆÈÜÒºµÄËá¼î¶È£¬¼òÊö²Ù×÷µÄÖ÷Òª²½Ö裺
¡£
£¨2£©ÔÚʵÑę́ÉÏÓÐÈýƿδÌù±êÇ©µÄÈÜÒº£¬ÒÑÖª·Ö±ðÊÇ̼ËáÄÆÈÜÒº¡¢ÇâÑõ»¯ÄÆÈÜÒººÍÏ¡ÑÎËá¡£ÎªÇø±ðÕâÈýÖÖÈÜÒº£¬ÔÚÀÏʦָµ¼Ï£¬ÐËȤС×éµÄͬѧ°ÑÕâÈýÖÖÈÜÒº°´A¡¢B¡¢C½øÐбàºÅ£¬È»ºó·Ö±ð¸÷È¡ÊÊÁ¿×÷ΪÑùÆ·¼ÓÈëµ½ÈýÖ§ÊÔ¹ÜÖУ¬½øÐÐÁËÈçÏÂͼËùʾµÄ̽¾¿»î¶¯£º
ѧ¿ÆÍõ
ѧ¿ÆÍõ
ѧ¿ÆÍõ
²½ÖèÒ»ÖУ¬CÎÞÃ÷ÏÔÏÖÏó£¬A¡¢BÈÜÒºµÄÑÕÉ«±ä³ÉºìÉ«£»
²½Öè¶þÖУ¬A¡¢BÈÜÒºµÄÑÕÉ«ÓɺìÉ«±ä³ÉÎÞÉ«£¬ÇÒBÈÜÒºÖÐÓÐÆøÅÝð³ö¡£
¢Ù¸ù¾ÝÉÏÊöʵÑéÏÖÏó¿ÉÖª£¬B¡¢CÈÜÒº·Ö±ðÊÇ_________¡¢__________¡£
¢ÚijС×éͬѧÔÚ½øÐв½ÖèһʵÑéʱ³öÏÖÒì³£ÏÖÏó£ºÍùAÈÜÒºÖмÓÈë·Ó̪ÊÔҺʱ£¬ÈÜÒºÑÕÉ«Ïȱä³ÉºìÉ«£¬Õñµ´ºóѸËÙ±ä³ÉÎÞÉ«¡£ÀÏʦָ³öÕâÊÇÒòΪÈÜҺŨ¶È¹ý´óÔì³ÉµÄ¡£½Ó×Å£¬ÀÏʦÍù¸ÃÊԹܵÄÈÜÒºÖмÓÈëÊÊÁ¿ÑÎËᣬ¹Û²ìµ½AÈÜÒºµÄÑÕÉ«ÓÖ±ä³ÉºìÉ«£¬´ËʱÈÜÒºÖк¬ÓеÄÈÜÖÊÖ÷ÒªÊÇ________£¨·Ó̪³ýÍ⣩¡£
£¨1£©
¢Ù
ÑùÆ·1: NaOH+HCl=NaCl+H2O
ÑùÆ·2: ÓÐÆøÅݲúÉú Na2CO3+2HCl=2NaCl+H2O+CO2¡ü
¢ÚÓò£Á§°ôպȡ̼ËáÄÆÈÜÒºµÎÔÚpHÊÔÖ½ÉÏ£¬°ÑÊÔÖ½³ÊÏÖµÄÑÕÉ«
Óë±ê×¼±ÈÉ«¿¨¶ÔÕÕ
(2)¢Ù̼ËáÄÆÈÜÒº Ï¡ÑÎËá
¢ÚÂÈ»¯ÄÆ¡¢ÇâÑõ»¯ÄÆ